a) A parachutist of mass mkg falls freely until his parachute is opened when it is opened, it experiences an upward resistance kv where v is its speed and k is a positive constant. Prove that after time t from the opening of its parachute, m dv = mg - kv. dt Prove that irrespective of his speed when he opens his parachute, his speed approaches a limiting value of mg provided he falls for sufficiently longtime. k m The parachutist falls freely from rest under gravity for a time and then opens his parachute. Prove 2k that the total distance he has fallen when his velocity is 3mg m2g (8ln2- 1)m. is 4k 8k2

Classical Dynamics of Particles and Systems
5th Edition
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Stephen T. Thornton, Jerry B. Marion
Chapter2: Newtonian Mechanics-single Particle
Section: Chapter Questions
Problem 2.34P: A particle is released from rest (y = 0) and falls under the influence of gravity and air...
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a) A parachutist of mass mkg falls freely until his parachute is opened when it is opened, it experiences
an upward resistance kv where v is its speed and k is a positive constant.
dv
Prove that after time t from the opening of its parachute, m
= mg - kv.
dt
Prove that irrespective of his speed when he opens his parachute, his speed approaches a limiting
value of mg
provided he falls for sufficiently longtime.
k
The parachutist falls freely from rest under gravity for a time and then opens his parachute. Prove
m
2k
that the total distance he has fallen when his velocity is
m2g
3mmg
is
(8ln2 - 1)m.
4k
8k2
Transcribed Image Text:a) A parachutist of mass mkg falls freely until his parachute is opened when it is opened, it experiences an upward resistance kv where v is its speed and k is a positive constant. dv Prove that after time t from the opening of its parachute, m = mg - kv. dt Prove that irrespective of his speed when he opens his parachute, his speed approaches a limiting value of mg provided he falls for sufficiently longtime. k The parachutist falls freely from rest under gravity for a time and then opens his parachute. Prove m 2k that the total distance he has fallen when his velocity is m2g 3mmg is (8ln2 - 1)m. 4k 8k2
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