dPbPb²+ (0.170 M)||Cd²+ (0.0720 M)| CdfPotential =b Zn|Zn²+ (0.0560 M)||T1³+ (9.22 × 10−² M), T1¹ (0.0230 M)| PtAn external voltage source is needed.The reaction will proceed spontaneously.Potential =Potential =VPt, H₂ (527 torr) HC1(1.63 × 10−4 M)||Ni²+ (0.0940 M)| NiPotential =VPb|Pb 1₂ (sat 'd), I¯ (0.0440 M)||Hg²+ (6.90 × 10-³I™Potential =VPotential =VPt, H₂ (2.70 atm) | NH3 (0.730 M), NH4+ (0.170 M)|| SHE³ M) | HgPt/TiO²+ (0.0610 M), Ti³+ (0.00510 M), H+ (1.70 × 10-² M)||VO²+ (0.1400 M), V³+ (0.0440 M), H+ (0.0290 M)|PtV

Answered: Image /qna-images/answer/a9782300-906c-4644-9d0e-bdef658856c1.jpg

a b с PbPb²+ (0.170 M)||Cd²+ (0.0720 M)| Cd Potential = An external voltage source is needed. The reaction will proceed spontaneously. V ZnZn²+ (0.0560 M)||T1³+ (9.22 × 10-² M), Tl¹ (0.0230 M)| Pt Potential = Potential = V Pt, H₂ (527 torr) HC1(1.63 × 10−4 M)||Ni²+ 4 M)||Ni²+ (0.0940 M) Ni V

a b с PbPb²+ (0.170 M)||Cd²+ (0.0720 M)| Cd Potential = An external voltage source is needed. The reaction will proceed spontaneously. V ZnZn²+ (0.0560 M)||T1³+ (9.22 × 10-² M), Tl¹ (0.0230 M)| Pt Potential = Potential = V Pt, H₂ (527 torr) HC1(1.63 × 10−4 M)||Ni²+ 4 M)||Ni²+ (0.0940 M) Ni V

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter10: Potentiometry And Redox Titrations

Section: Chapter Questions

Problem 2P

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