A ball is launched from the top of a 60 ft. tall building with an initial velocity of 48 ft. per second. Its height aftert seconds is given by the equation, h(t) = - 16t + 48t + 60. 27. At what times will the ball be 92 feet above the ground? 28. Find the height of the ball after 1.5 seconds.

A ball is launched from the top of a 60 ft. tall building with an initial velocity of 48 ft. per second. Its height aftert seconds is given by the equation, h(t) = - 16t + 48t + 60. 27. At what times will the ball be 92 feet above the ground? 28. Find the height of the ball after 1.5 seconds.

Elementary Algebra

17th Edition

ISBN:9780998625713

Author:Lynn Marecek, MaryAnne Anthony-Smith

Publisher:Lynn Marecek, MaryAnne Anthony-Smith

Chapter10: Quadratic Equations

Section10.4: Solve Applications Modeled By Quadratic Equations

Problem 159E: A bullet is fired straight up from a BB gun with initial velocity 1120 feet per second at an initial...

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Question

How can I solve this problem ? Please show each step

A ball is launched from the top of a 60 ft. tall building with an initial velocity of 48 ft. per second. Its height aftert seconds
is given by the equation, h(t):
- 16t + 48t + 60.
%3D
|
27.
At what times will the ball be 92 feet above the ground?
28.
Find the height of the ball after 1.5 seconds.

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