Question
Asked Oct 31, 2019

A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=104t - 16t2 . After how long will it reach its maximum height?

Do not round your answer.

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Expert Answer

Step 1

In order to find the maxima or minima, first find the derivative and equate the derivative to zero, which is the critical point(s), then substitute the point(s) in second derivative to check the maxima and minima.

If the second derivative is less than zer...

The given function is h(t)=104t -1612
dh
d
(104r-16
dt
dt
=104 -3212
Equate the derivative to zero.
104 32 0
-32t-104
-104
t =
-32
104
t =
32
t 3.25
The critical point is t 3.25
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The given function is h(t)=104t -1612 dh d (104r-16 dt dt =104 -3212 Equate the derivative to zero. 104 32 0 -32t-104 -104 t = -32 104 t = 32 t 3.25 The critical point is t 3.25

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