A ball is thrown with an initial speed of 20 ?/? from one end of a horizontal platform with a length of 48 ? and a height of 32 ? at angle of 37° to the the horizontal. At the same time a man who is standing on the ground starts from rest and moves with a constant acceleration of ?(see Figure). (a) Find the time of flight of the ball (b) What should be the acceleration of the man so that he can hold the ball before it falls? cos53o =sin37o=0.6 cos37o =sin53o=0.8 g=9.8 m/s2

A ball is thrown with an initial speed of 20 ?/? from one end of a horizontal platform with a length of 48 ? and a height of 32 ? at angle of 37° to the the horizontal. At the same time a man who is standing on the ground starts from rest and moves with a constant acceleration of ?(see Figure). (a) Find the time of flight of the ball (b) What should be the acceleration of the man so that he can hold the ball before it falls? cos53o =sin37o=0.6 cos37o =sin53o=0.8 g=9.8 m/s2

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Description: A ball is thrown with an initial speed of 20 ?/? from one end of a horizontal platform with a length of 48 ? and a height of 32 ? at angle of 37° to the the horizontal. At the same time a man who is standing on the ground starts from rest and moves w

An Introduction to Physical Science

14th Edition

ISBN:9781305079137

Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Publisher:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Chapter2: Motion

Section: Chapter Questions

Problem 12MC: A football is thrown on a long pass. Compared to the balls initial horizontal velocity, the velocity...

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A ball is thrown with an initial speed of 20 ?/? from one end of a horizontal platform with a length of 48 ? and a height of 32 ? at angle of 37° to the the horizontal. At the same time a man who is standing on the ground starts from rest and moves with a constant acceleration of ? (see Figure). (a)Find the time of flight of the ball (b) What should be the acceleration of the man so that he can hold the ball before it falls? cos53=sin37=0.6 cos37=sin53=0.8 g=9.8 m/s2
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