A ball, mass 25g, velocity 30cm/s southward, collides with another ball, mass 10g, moving along the same line with a velocity of 15cm/s southward. After collision, the 25g ball has a velocity of 22cm/s southward. What is the velocity of the 10g ball? Steps to follow: 1. Write the given 2. What is asked? 3. Formula to be used 4. Solution 5. Final answer and unit

A ball, mass 25g, velocity 30cm/s southward, collides with another ball, mass 10g, moving along the same line with a velocity of 15cm/s southward. After collision, the 25g ball has a velocity of 22cm/s southward. What is the velocity of the 10g ball? Steps to follow: 1. Write the given 2. What is asked? 3. Formula to be used 4. Solution 5. Final answer and unit

Name: Show the complete solution. Please make sure that your handwritten is
Uploaded: 2024-03-20T06:57:37.000Z
Channel: Bartleby
Description: Show the complete solution. Please make sure that your handwritten is readable. Thank you. Learning Task 2:PROBLEM SOLVINGDirections: Analyze the situation and answer carefully.A ball, mass 25g, velocity 30cm/s southward, collides with another ball,

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter38: Relativity

Section: Chapter Questions

Problem 38P

See similar textbooks

Similar questions

Three objects AA, BB, and CC are moving as shown in the figure below (Figure 1). Assume that vAvAv_A = 12.0 m/sm/s, vBvBv_B = 9.6 m/sm/s, and vCvCv_C = 2.8 m/sm/s. a) Find the xx-component of the net momentum of the particles if we define the system to consist of BB and CC. Express your answer in kilogram meters per second. b) Find the xx-component of the net momentum of the particles if we define the system to consist of all three objects. Express your answer in kilogram meters per second. both answers are not zero, tried that its wrong.
NOTE :: COMPLETE SOLUTION AND ANSWER ONLY NO NEED EXPLANATION 3. Given the equation and using the Naïve Gauss elimination method, solve the unknown and consider 4 significant digits in your answer. 0.0030x1 + 55.23x2 = 58.12 6.239x1 – 7.123x2 = 47.23 4. The table is the data for the velocity of the rocket as a function of time. To find the velocity at t = 21 s, used the quadratic polynomial, v(t ) = at2 + bt + c to approximate the velocity profile. t (s) 0 14 15 20 30 35 v(t ) (m / s) 0 227.04 362.78 517.35 602.97 901.67 What is the set equations that will find a, b and c?
ANSWERS must be in 3 decimal places A 50 kg mass is sitting on a frictionless surface. An unknown constant force pushes the mass for 2 seconds until the mass reaches a velocity of 3 m/s. 1. What was the impulse acting on the mass? 2. What is the final momentum of the mass? 3. What was the force acting on the mass?
A ball of mass 10 kg makes a head-on elastic collision with a second ball (at rest) and rebounds with a speed equal to 0.3 its original speed. What is the mass (in kg) of the second ball? (Could you please provide a step by step formula?) (This is the Fifth Time I'm asking Bartleby for help with this question, please explain in the diagram in detail please, step by step. ) (For example. for some reason, one of the variables turns from 0.3 into 0.7 m/s, please explain how and why) (Please lable velocities, masses ex. properly as which ones are the initials, finals, which mass belongs to which one.)
an object with a length of 0.73m and mass of 107kg was thrown at a velocity of 1.07 x 10^8 m/s. if it collides with a stationary block, what momentum in kgm/s will the block absorb from the object? solve it correctly please. I will rate accordingly.
A ball of mass 10 kg makes a head-on elastic collision with a second ball (at rest) and rebounds with a speed equal to 0.3 its original speed. What is the mass (in kg) of the second ball? (Could you please provide a step by step formula?) (This is the Fourth Time I'm asking Bartleby for help with this question, please explain in the diagram in detail please, step by step. ) (For some reason, one of the variables turns from 0.3 into 0.7 m/s, please explain) (If you cannot work with a rebound speed of 0.3, use 0.2)
A 110-kilogram tackler traveling at 2.5 m/s makes a head-on collision with and successfully carries an 88-kilogram halfback traveling at 5.0 m/s. Part A How fast will they be going together just after they smash into each other? Include the correct units and round your result to two major numbers. Submit 31 Value = v' Units Requested: O
In this problem we will observe how the momentum of an electron changes as its velocity approaches the speed of light. The mass of an electron is 9.109 × 10-31 kg Part (a) First, what is the momentum of an electron which is moving at the speed of a car on a highway, say 31 m/s, in kilogram meters per second? Part (b) What is the momentum of an electron moving at 18 % of the speed of light, in kilogram meters per second? Part (c) What is the momentum of an electron moving at 81 % of the speed of light, in kilogram meters per second? Part (d) What is the non-relativistic momentum of an electron moving at this speed (81 % of the speed of light), in kilogram meters per second? Part (e) When the electron is moving at 81 % of the speed of light, how many times greater is the relativistic momentum than the non-relativistic
I did my lab for Momentum in Conservation in Momentum and I want to know What was the difference in momentum? Was momentum conserved? according to the pictures I posted below of the results.
this is a multi step problem but I am just having trouble with this part of the problem. Here are the values that I correctly calculated: mass of particle 1=6 kg initial velocity for particle 1= 185i+138j final velocity for particle 1= -68.89i+-50.67j I am trying to find: What is the change in kinetic energy for particle 1? I understand I have to use KT= 1/2*m*(vf2-vi2) but I keep getting the wrong answer can you please help?
A ball of mass 10 kg makes a head-on elastic collision with a second ball (at rest) and rebounds with a speed equal to 0.3 its original speed. What is the mass (in kg) of the second ball? (Could you please provide a step by step formula?) (This is the Third time I'm asking Bartleby for help with this question, please explain in the diagram in detail please)
Particle A of mass m, initial velocity 20i (m/s) has a collision with a stationary particle B of mass 2m. After collision, VA(final)=10i+5j (m/s) I need help understanding how does the i and j effect the formula for collision problems? I know the usual collision probleam steps but don't understand how this would effect the steps to solve the questions asked from this scenerio such as finding VB(final) if the system linear momentum is conserved in both directions. or calculating what the velocities of center of the system are before and after collision?