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- 1. a)What is the momentum of a 1.20x 104kg truck whose velocity is 50.0 m/s? b)What velocity must a 6000 kg truck attain in order to have the same momentum? c)What velocity must it attain to have the same kinetic energy?A projectile of mass 0.719 kg is shot straight up with an initial speed of 22.1 m/s. (a) How high would it go if there were no air resistance? (b) If the projectile rises to a maximum height of only 8.70 m, determine the magnitude of the average force due to air resistance.Identify whether the following is a scalar quantity or a vector quantity. a. 800 J of work b. 120 N along the positive x-axis c. 200 m d. 9.8 m/s² along the negative y-axis e. 50 kg-m/s' momentum going toward the south
- A 2.64 -g bullet moving at 280 m/s enters and stops in an initially stationary 2.10−kg wooden block on a horizontal frictionless surface. (a) What's the speed of the bullet/block combination?(b) What fraction of the bullet's kinetic energy was lost in this perfectly inelastic collision? (c) How much work was done in stopping the bullet? (d) If the bullet penetrated 5.00 cm into the wood, what was the average stopping force?A 0.250 kg hammer is moving horizontally at 4.50 m/s when it strikes a nail and comes to rest after driving it 1.00 cm into a board.(a) Calculate the duration of the impact....................s(b) What was the average force exerted on the nail?...................NA) Two blocks of clay, one of mass 1.00 kg and one of mass 3.00 kg, undergo a completely inelastic collision. Before the collision one of the blocks is at rest and the other block is moving with kinetic energy 32.0 JJ. If the 3.00 kg block is initially at rest and the 1.00 kg block is moving, what is the initial speed of the 1.00 kg block? B) What is the common final speed of the two blocks? C) How much kinetic energy is lost in the collision? D) If the 1.00 kg block is initially at rest and the 3.00 kg block is moving, what is the initial speed of the 3.00 kg block? E) What is the common final speed of the two blocks in case of the 1.00 kgkg block is initially at rest? F) How much kinetic energy is lost in the collision in case of the 1.00 kg block is initially at rest? G) In which case is more of the initial kinetic energy lost in a completely inelastic collision: a moving object collides (i) with a heavier object at rest or (ii) with a lighter object at rest? H) A 0.500 kg block of…
- A 300-kg flatcar 29 mm long is moving with a speed of 7.0 m/s along horizontal frictionless rails. A 90-kg worker starts walking from one end of the car to the other in the direction of motion, with speed of 3.0 m/s with respect to the car. Part A In the time it takes for him to reach the other end, how far has the flatcar moved?A box of mass m = 0.31 kg is set against a spring with a spring constant of k1 = 549 N/m which has been compressed by a distance of 0.1 m. Some distance in front of it, along a frictionless surface, is another spring with a spring constant of k2 = 444 N/m. a.) How far d2, in meters, will the second spring compress when the box runs into it? b.) How fast v, in meters per second, will the box be moving when it strikes the second spring? c.) Now assume friction is present on the surface in between the ends of the springs at their equilibrium lengths, and the coefficient of kinetic friction is μk = 0.5. If the distance between the springs is x = 1 m, how far d2, in meters, will the second spring now compress?In Figure, block A (mass 0.8 kg) slides into block B (mass 1.2 kg), along a frictionless surface.The directions of three velocities before (i) and after (f) the collision are indicated in the figure; the corresponding speeds are vAi =1.9 m/s, vBi =4.9 m/s, and vBf =2.5 m/s.What are the (a) magnitude and (b) direction (left or right) of velocity vAf ? (c) Calculate the total kinetic energy of the system before and after the collision. Is the collision elastic?
- A cube of mass m = 0.16 kg is set against a spring with a spring constant of k1 = 599 N/m which has been compressed by a distance of 0.1 m. Some distance in front of it, along a frictionless surface, is another spring with a spring constant of k2 = 252 N/m. The cube is not connected to the first spring and may slide freely. a.) How far, d2, in meters, will the second spring compress when the cube runs into it? b.) How fast, v2 in meters per second, will the cube be moving when it strikes the second spring? c.) Now assume that the surface is rough (that is not frictionless). You perform the experiment and observe that the second spring only compress a distance d2/2. How much energy in Joules was lost to friction?A 5.08×104 kgkg railroad car moves on frictionless horizontal rails until it hits a horizontal spring stopper with a force constant of 4.09×105 N/mN/m . When the railroad car comes to a complete stop, the compression of the spring stopper is 30 cmcm . How fast was the railroad car initially?Just a little something on momentum and kinetic energy. As a reminder, momentum is a vector and: p = mv K = 1/2 mv2 = 1/2 pv = p2/2m In terms of the dot product: v2 = v⋅v, p2 = p⋅p, and pv = p⋅v. Unlike speed vs. velocity, but like all other vectors, momentum may refer to the magnitude of the momentum vector. Now, answers the following questions: 1) A 7-kg particle goes 96 m/s. Calculate its momentum in kg*m/s. (This requires an exact answer.) 2) A 7-kg particle's momentum is (392, 61) kg*m/s. Calculate its kinetic energy. 3) A pebble and a grapefruit have the same momentum. Which has the greater kinetic energy?