Question

Asked Oct 8, 2019

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A basketball player has a free throw percentage of 93%. What is the probability she misses at least one of his next 27 free throws?

Step 1

The probability of she misses at least one of his next 27 free throws is obtained below:

Let *X* be the number of throws until she the first missed, 93% of player has a free throw, that is *q* = 0.93. 7% of does not make her free throw, that is *p* = 0.07 (1–0.93).

Therefore, the distribution is binomial distribution with sample size 27 and probability of success 0.07. That is, *X*~ Binomial (27, 0.07).

The formula for the probability of binomial distribution is,

Step 2

The required proba...

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