Question
Asked Dec 3, 2019
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A bat's squeak takes 0.146 seconds to return after reflecting off a moth. How far away is the bat from the moth? The speed of sound in air is 343 m/s. 

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Step 1

Given:

Time taken by sound to travel up to moth and return to bat (T)= 0.146 s.

Speed of sound in air (v)= 343 m/s

Step 2

Time taken by sound wave to travel up to moth is given as (t)

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T t = 2 0.146 t = 2 t 0.073 s

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Step 3

Distance between bat and ...

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d =v.t d = 343 x 0.073 d = 25.039 m

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