A beam has a width of 200 mm and has an effective depth of 300 mm. It is cantilevered at a span of 4 m and has a uniformly distributed dead load of 15 KN 771 including its own weight. 12 mm- diameters bars are used as stirrups for the beam width. fy= 275 MPa. Use f'c = 20.7 MPa 66. Determine the ultimate critical shear occurring on the beam. a. 72 kN b. 64.8 kN c. 75 KN d. 66.6 kN 67. Compute for the theoretical spacing needed for critical shear. a. 100 mm b. 150 mm c. 440.19 mm d. 310.43 mm 68. Compute for the maximum spacing needed for critical shear. a. 100 mm b. 150 mm c. 440.19 mm d. 310.43 mm

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter5: Stresses In Beams (basic Topics)
Section: Chapter Questions
Problem 5.11.11P: The three beams shown have approximately the same cross-sectional area. Beam 1 is a W 14 X 82 with...
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A beam has a width of 200 mm and has an
effective depth of 300 mm. It is
cantilevered at a span of 4 m and has a
uniformly distributed dead load of 15
KN
771
including its own weight.
12 mm-
diameters bars are used as stirrups for the
beam width. /y = 275 MPa. Use f'c =
20.7 MPa
66. Determine the ultimate critical shear
occurring on the beam.
a. 72 kN
b. 64.8 kN
c. 75 KN
d. 66.6 kN
67. Compute for the theoretical spacing
needed for critical shear.
a. 100 mm
b. 150 mm
c. 440.19 mm
d. 310.43 mm
68. Compute for the maximum spacing
needed for critical shear.
a. 100 mm
b. 150 mm
c. 440.19 mm
d. 310.43 mm
Transcribed Image Text:A beam has a width of 200 mm and has an effective depth of 300 mm. It is cantilevered at a span of 4 m and has a uniformly distributed dead load of 15 KN 771 including its own weight. 12 mm- diameters bars are used as stirrups for the beam width. /y = 275 MPa. Use f'c = 20.7 MPa 66. Determine the ultimate critical shear occurring on the beam. a. 72 kN b. 64.8 kN c. 75 KN d. 66.6 kN 67. Compute for the theoretical spacing needed for critical shear. a. 100 mm b. 150 mm c. 440.19 mm d. 310.43 mm 68. Compute for the maximum spacing needed for critical shear. a. 100 mm b. 150 mm c. 440.19 mm d. 310.43 mm
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