A biochemist carefully measures the molarity of salt in 56. mL of photobacterium cell growth medium to be 82. mM. Unfortunately, a careless graduate student forgets to cover the container of growth medium and a substantial amount of the solvent evaporates. The volume of the cell growth medium falls to 3.1 mL. Calculate the new molarity of salt in the photobacterium cell growth medium. Be sure your answer has the correct number of significant digits. I| mM ?
Q: A chemistry student weighs out 0.0977 g of acetic acid (HCH,CO,) into a 250. mL volumetric flask and…
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Q: A chemistry student weighs out 0.0345 g of chloroacetic acid (HCH,CICO,) into a 250. mL volumetric…
A: Molarity is defined as total number of solute present in 1000 ml of solution . For neutralisation…
Q: A chemistry student weighs out 0.101 g of hypobromous acid (HBRO) into a 250. mL volumetric flask…
A: Given: Mass of hypobromous acid = 0.101 g Volume of volmetric flask = 250 mL Molarity of NaOH…
Q: An analytical chemist weighs out 0.029 g of an unknown monoprotic acid into a 250 mL volumetric…
A: Assuming the monoprotic acid is HA. Hence the reaction between the acid and base is HA + NaOH…
Q: A chemistry student weighs out 0.186 g of sulfurous acid (H, SO,), a diprotic acid, into a 250. mL…
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Q: A chemistry student weighs out 0.0457 g of formic acid (HCHO,) into a 250. mL volumetric flask and…
A: Given- Weight of formic acid =0.0457g Volume volumetric flask=250mL Concentration of NaOH =0.1100 M…
Q: An analytical chemist weighs out 0.120 g of an unknown diprotic acid into a 250 mL volumetric flask…
A: Unknown Diprotic acid = 0.120 gm, its formula will be H2A The reaction of NaOH with H2A
Q: A chemistry student weighs out 0.176 g of sulfurous acid (H,SO,), a diprotic acid, into a 250. mL…
A: Given : mass of H2SO3 = 0.176 g Since molar mass of H2SO3 = Atomic mass of H X 2 + Atomic mass of S…
Q: A chemistry student weighs out 0.212 g of chloroacetic acid (HCH,CICO,) into a 250. mL volumetric…
A: Chloroacetic acid is a monobasic acid and NaOH is a monoacidic base. Thus, an equal number of moles…
Q: A chemistry student weighs out 0.0353 g of acetic acid (HCH,CO,) into a 250. mL volumetric flask and…
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Q: A chemistry student weighs out 0.120 g of lactic acid (HCH,O,) into a 250. mL volumetric flask and…
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Q: A chemistry student weighs out 0.150g of phosphoric acid H3PO4 , a triprotic acid, into a…
A: The 250 ml of solution is equal to 0.250 L. The concentration of phosphoric solution (M) is…
Q: A chemistry student weighs out 0.166 g of chloroacetic acid (HCH, CICO,) into a 250. mL volumetric…
A: Chloric acetic acid reacts with sodium hydroxide to form sodium chloroacetate and water. The…
Q: An analytical chemist weighs out 0.101g of an unknown diprotic acid into a 250 mL volumetric flask…
A: Neutralization reaction : Equivalent amount of acid reacts with a equivalent amount of base This…
Q: A chemistry student weighs out 0.0918 g of hypobromous acid (HBrO) into a 250. mL volumietric flask…
A:
Q: A chemistry student weighs out 0.0973 g of phosphoric acid (H3PO4, a triprotic acid, into a 250. mL…
A: Given:Mass of phosphoric acid=0.0973 gVolume=250 mLMolarity of NaOH=0.1100 M Conversion:From mL to…
Q: A chemistry student weighs out 0.417 g of citric acid (H,C H¸O,), a triprotic acid, into a 250. mL…
A: Given, Weigh of citric acid = 0.417 g Volume of citric acid = 250 mL Molarity of NaOH = 0.1000 M…
Q: A chemistry student weighs out 0.0955 g of ascorbic acid (H,C,H,O6), a diprotic acid, into a 250. mL…
A: Molar mass of ascorbic acid = 176.12 g/mol mass o f ascorbic acid = 0.0955 g Number of moles of…
Q: A chemistry student weighs out 0.199 g of hypobromous acid (HBro) into a 250, mL volumetric flask…
A: Given: mass of HBrO = 0.199 g Volume = 250 mL 0.1000 M NaOH
Q: A chemistry student weighs out 0.179 g of chloroacetic acid (HCH,CiCo,) into a 250. mL volumetric…
A: The molar mass of chloroacetic acid is 94.5 g/mol. The number of moles of chloroacetic acid is…
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Q: A chemistry student weighs out 0.270 g of citric acid (H;C,H;0;), a triprotic acid, into a 250. mL…
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Q: A chemistry student weighs out 0.234 g of chloroacetic acid (HCH,CICO,) into a 250. mL volumetric…
A:
Q: A chemistry student weighs out 0.166 g of ascorbic acid (H,C,H,O), a diprotic acid, into a 250. mL…
A: Ascorbic acid reacts with sodium hydroxide to form sodium ascorbate and water. The equation for the…
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Q: An analytical chemist weighs out 0.109 g of an unknown triprotic acid into a 250 mL volumetric flask…
A:
Q: An analytical chemist weighs out 0.159 g of an unknown monoprotic acid into a 250 mL volumetric…
A: Neutralization reaction : Equivalent amount of acid reacts with a equivalent amount of base This…
Q: A chemistry student weighs out 0.228 g of phosphoric acid (H,PO, a triprotic acid, into a 250. mL…
A: This is an acid base titration where H3PO4 is a triprotic acid and the reaction taking place will…
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A:
Q: A chemistry student weighs out 0.218 g of ascorbic acid (H,C,H,O), a diprotic acid, into a 250. mL…
A: Given: mass of ascorbic acid = 0.218 g Molar mass of ascorbic acid , H2C6H6O6 = 176 g/mol No. of…
Q: A chemistry student weighs out 0.146 g of lactic acid (HC,H,O,) into a 250. mL volumetric flask and…
A: Mass of lactic acid = 0.146 gMolar mass of lactic acid = 90 g/molMoles of lactic acid = Mass of…
Q: An analytical chemist weighs out 0.073 g of an unknown monoprotic acid into a 250 mL volumetric…
A: Given : Mass of monoprotic acid = 0.073 g Concentration of NaOH = 0.1200 M And volume of NaOH…
Q: An analytical chemist weighs out 0.181 g of an unknown diprotic acid into a 250 mL volumetric flask…
A: Let the diprotic acid be H2A. The reaction between the diprotic acid and NaOH is shown as: H2A +…
Q: A chemistry student weighs out 0.106 g of sulfurous acid (H, So,), a diprotic acid, into a 250. mL…
A:
Q: A chemistry student weighs out 0.178 g of phosphoric acid (H,PO), a triprotic acid, into a 250. mL…
A:
Q: An analytical chemist weighs out 0.141 g of an unknown diprotic acid into a 250 mL volumetric flask…
A: Given, Mass of unknown diprotic acid = 0.141 g. Volume of flask = 250 mL Molarity of NaOH = 0.1100 M…
Q: An analytical chemist weighs out 0.280g of an unknown diprotic acid into a 250mL volumetric flask…
A: As per the data given in the question,Weight of unknown diprotic acid = 0.280 gVolume of solution…
Q: A chemistry student weighs out 0.0690 g of hypobromous acid (HBrO) into a 250. mL volumetric flask…
A: Given: Mass of HBrO = 0.0690 g. And concentration of NaOH = 0.1700 M
Q: A chemistry student weighs out 0.181 g of phosphoric acid (H,PO), a triprotic acid, into a 250. mL…
A: First of all,we calculate the Molarity of phosphoric acid. Molarity is the number of moles of solute…
Q: A chemistry student weighs out 0.145 g of sulfurous acid (H,SO,), a diprotic acid, into a 250. mL…
A: The solution is as follows :
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A: Number of moles of a substance is equal to the mass of a substance divided by molar mass. Write the…
Q: A biochemist carefully measures the molarity of salt in 34. mL of photobacterium cell growth medium…
A:
Q: A chemistry student weighs out 0.0792 g of formic acid (HCHO,) into a 250. mL volumetric flask and…
A: Answer :- 34.4 ml The Volume of NaOH needed to reach equivalence point = 34.4 ml.…
Q: A chemistry student weighs out 0.259 g of ascorbic acid (H,C,H,O,), a diprotic acid, into a 250. mL…
A: Given, Mass of ascorbic acid is 0.259 g The volume of the volumetric flask is 250 ml Titrated with…
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A:
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A:
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A: Since Lactic acid is a weak monoprotic acid Hence it will react with NaOH as NaOH + HC3H5O3…
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A:
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- In the first step of this process sodium bromide is dissolved in water. It is mentioned that not all the sodium bromide dissolves. The solubility of sodium bromide in water is 0.9432g/mL. For the quantities used in this experiment, would all the NaBr dissolve if the mixture were stirred long enough? Justify your answer. 78g sodium bromide 75ml distilled waterWhich of the following given statements is false? 1. The electrical conductivity of water is dependent on the temperature of the water sample. Removal of suspended particles by sedimentation depends upon the size and specific gravity of those particles. Suspended solids retained on a filter may remain in suspension if their specific gravity is similar to water while very dense particles passing through the filter may settle. Sodium hydroxide and sodium chloride are both bases. 2. In a sedimentation process, the solid particles settled at the bottom of the container because they are heavier than water and are acted upon by gravity. In the process of distillation, the condenser helps in the conversion of the vapor that goes inside it into liquid. After filtering a mixture using a filter paper, there is more solute at the bottom of the container compared to the contents of the filter paper. In the reaction between dry ferrous sulfate and dry potassium ferricyanide, no change is observed.…Which of the following is the best option for transferring 20 mL of a solution? Use a 20 mL Mohr pipette once Use a 10 mL Mohr pipette twice Use a 10 mL volumetric pipette twice Use a 5mL serological pipette 4 times Which of the following glassware is best used for drying solid samples in an oven? Beaker Crucible Erlenmeyer flask Watch glass Which of the following glassware is best used for slow dispensing of 47.00 mL of a solution? Mohr Pipette Volumetric Pipette Burette Graduated Cylinder
- A flask of 25.0 mL with an unknown concentration of magnesium hydroxide completely reacts with 18.0 mL of 1.0 M hydrochloric acid solution according to the equation : HCl (aq) + Mg(OH)2 (aq) -> MgCl2(aq) + H2O (l) Determine the concentration of the magnesium hydroxide solution using dimensional analysis when possible.please see image attached: A chemistry student weighs out 0.146 g of chloroacetic acid into a 250. mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1400M(molarity) NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the equivalence point. Round your answer to 3 significant digits.Identify and explain the mistakes made in the following laboratory protocols: A 10.00 mM solution of glucose (FW 180.16 g/mole) was prepared by first adding 180.16 mg of glucose to a 100 mL empty volumetric flask, and then DI H2O was added to the volumetric flask until the meniscus reached the 100 mL volume mark. The flask was capped and the solution vigorously mixed until the glucose completely dissolved.
- A 1 mL sample of glycogen was calculated to contain 35 µmol (micromole) glucose. To 1 mL of this sample was added 2 mL of 2 M HCL. It was then hydrolysed by boiling the solution for 15 minutes. After boiling the hydrolysate was cooled and made up with H2O to a final volume of exactly 10 mL. The glucose was measured in this solution and found to have a concentration of 570 µg/mL (microgram/milliliter). i) Calculate the mass (mg) of glucose in the 10 mL of hydrolysate. As the 1mL of glycogen sample was made up to a final volume of 10 mL, this mass of glucose was produced by the hydrolysis of the original 1 mL glycogen sample. ii) Calculate the amount (µmol) of glucose produced by the hydrolysis of the glycogen sample. iii) Calculate the purity of the glycogen used in the sample as % Purity = (moles of measured glucose/ moles of calculated glucose in glycogen) *100 iv) state your answer in a complete sentence.A 1 mL sample of glycogen was calculated to contain 21 µmol (micromole) glucose. To 1 mL of this sample was added 2 mL of 2 M HCl. It was then hydrolysed by boiling the solution for 15 minutes. After boiling the hydrolysate was cooled and made up with H2O to a final volume of exactly 10 mL. The glucose was measured in this solution and found to have a concentration of 340 µg/mL (microgram/milliliter). i) Calculate the mass (mg) of glucose in the 10 mL of hydrolysate. As the 1 mL of glycogen sample was made up to a final volume of 10 mL, this mass of glucose was produced by the hydrolysis of the original 1 mL glycogen sample. ii) Calculate the amount (µmol) of glucose produced by the hydrolysis of the glycogen sample. iii) Calculate the purity of the glycogen used in the sample as % Purity = (moles of measured glucose/ moles of calculated glucose in glycogen) *100 iv) state your answer in a complete sentence. Show your working out such that the marker can easily understand it.…The toxicity of DDT (C14H9Cl5) led to a ban on its use in the United States in 1972. Determinations of DDT concentrations in groundwater samples from Pennsylvania between 1969 and 1971 yielded the following results: Location Sample Size Mass of DDT Orchard 253 mL 0.0310 mg Residential 1.77 L 0.0350 mg Residentialafter a storm 51.5 mL 0.570 mg Express these concentrations in millimoles per liter. Orchard= ___mmol/l Residental=___ mmol/l Residential after a storm=___ mmol/L
- BSA for concentration measurements is often prepared as a 10 mg/mL stock solution. Suppose you wish to prepare a series of 10 mL solutions of BSA at 1.0, 0.8, 0.6, 0.4, and 0.2 mg/mL. Using the dilution equation C1 × V1 = C2 × V2, you plan to do this by transferring a calculated volume (V1) of the 10 mg/mL (C1) into a clean test tube, then adding water in sufficient volume to produce 10 mL (V2) at the desired concentration (C2). Complete the table below, showing the volume of stock 10 mg/mL solution you need to add to each tube, and the volume of water you need to add to each. Also, convert the desired mg/mL concentration values to their equivalent in μM (micromolar; 10-6 M).An aqueous solution of sodium chloride,NaCl , is made by dissolving 1.01 grams of sodium chloride in sufficient water in a 50.0 mL volumetric flask, and then adding enough water to fill the flask to the mark. What is the weight/volume percentage of sodium chloride in the solution? Weight/volume percentage = %A) An aqueous solution of sodium nitrate, NaO3, is made by dissolving 21.6 grams of sodium nitrate in sufficient water in a 500. mL volumetric flask, and then adding enough water to fill the flask to the mark. What is the weight/volume percentage of sodium nitrate in the solution? Weight/volume percentage = _______% B) An aqueous solution of ammonium fluoride, NH4F, is made by dissolving 32.4 grams of ammonium fluoride in sufficient water in a 500. mL volumetric flask, and then adding enough water to fill the flask to the mark. What is the weight/volume percentage of ammonium fluoride in the solution? Weight/volume percentage = ________%