A bird flies 2.5 km [W 40.° N] and then 1.5 km [N20.° E]. A sketch of the bird's motion (not to scale) is shown below. Which of the following formulas represents the correct expression to find the magnitude of Adg :? Ad2= 1.5 km [N 20. °E] N 20.9 AdR Ad1= 2.5 km [W 40.°N] 40. O Ad,? = 2.5² + 1.5² – 2(2.5)(1.5)cos110.0 O Ad,? = 2.52 + 1.52 – 2(2.5)(1.5)cos120.0 O Ad,? = 2.52 + 1.52 - 2(2.5)(1.5)cos 60.0 O Ad,? = 2.52 + 1.52 - 2(2.5)(1.5)cos70.0 O Ad,? = 2.52 + 1.52 - 2(2.5)(1.5)cos20.0

College Physics
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Chapter2: Motion In One Dimension
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Problem 72AP: In Bosnia, the ultimate test of a young nuns courage used to be to jump off a 400-year-old bridge...
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A bird flies 2.5 km [W 40.° N ] and then 1.5 km [N20.° E]. A sketch of the bird's motion (not to
scale) is shown below. Which of the following formulas represents the correct expression to find the
magnitude of
-?
Adr
Ad2= 1.5 km [N 20. °E]
E
20.5
AdR
Ad1= 2.5 km [W 40.°N]
40.°
O ad,
= 2.52 + 1.5² – 2(2.5)(1.5)cosl10.0
O Ad,? = 2.5² + 1.5² – 2(2.5)(1.5)cos120.0
= 2.52 + 1.52 – 2(2.5)(1.5)cos 60.0
O ad, =
= 2.52 + 1.52 – 2(2.5)(1.5)cos70.0
O ad,
= 2.52 + 1.52 - 2(2.5)(1.5)cos20.0
Transcribed Image Text:A bird flies 2.5 km [W 40.° N ] and then 1.5 km [N20.° E]. A sketch of the bird's motion (not to scale) is shown below. Which of the following formulas represents the correct expression to find the magnitude of -? Adr Ad2= 1.5 km [N 20. °E] E 20.5 AdR Ad1= 2.5 km [W 40.°N] 40.° O ad, = 2.52 + 1.5² – 2(2.5)(1.5)cosl10.0 O Ad,? = 2.5² + 1.5² – 2(2.5)(1.5)cos120.0 = 2.52 + 1.52 – 2(2.5)(1.5)cos 60.0 O ad, = = 2.52 + 1.52 – 2(2.5)(1.5)cos70.0 O ad, = 2.52 + 1.52 - 2(2.5)(1.5)cos20.0
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