A block of mass 0.74 kg is suspended by a string which is wrapped so that it is at a radius of 0.069 m from the center of a pulley. The moment of inertia of the pulley is 4.90×10-3 kg·m2. There is friction as the pulley turns. The block starts from rest, and its speed after it has traveled downwards a distance of D= 0.77 m, is 2.133 m/s. Calculate the amount of energy dissipated up to that point.

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Chapter8: Rotational Motion
Section8.2: Rotational Dynamics
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A block of mass 0.74 kg is suspended by a string which is wrapped so that it is at a radius of 0.069 m from the center of a pulley. The moment of inertia of the pulley is 4.90×10-3 kg·m2. There is friction as the pulley turns. The block starts from rest, and its speed after it has traveled downwards a distance of D= 0.77 m, is 2.133 m/s. Calculate the amount of energy dissipated up to that point.

Course Contents » ... » HW 12 » Mass Pulling a pulley
Timer
A Notes a Evaluate A Feedback A Print O Info
A block of mass 0.74 kg is suspended by a string which is wrapped so that it is at a radius of 0.069 m from the center of a pulley. The moment of
inertia of the pulley is 4.90×10-3 kg-m2. There is friction as the pulley turns. The block starts from rest, and its speed after it has traveled
downwards a distance of D= 0.77 m, is 2.133 m/s. Calculate the amount of energy dissipated up to that point.
Mp
Mb
Submit Answer Tries 0/15
Transcribed Image Text:Course Contents » ... » HW 12 » Mass Pulling a pulley Timer A Notes a Evaluate A Feedback A Print O Info A block of mass 0.74 kg is suspended by a string which is wrapped so that it is at a radius of 0.069 m from the center of a pulley. The moment of inertia of the pulley is 4.90×10-3 kg-m2. There is friction as the pulley turns. The block starts from rest, and its speed after it has traveled downwards a distance of D= 0.77 m, is 2.133 m/s. Calculate the amount of energy dissipated up to that point. Mp Mb Submit Answer Tries 0/15
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