A block of mass m₁ = 16.4 kg is on a frictionless table to the left of a second block of mass m₂ = 17.7 kg, attached by a horizontal string (see the figure below). |HINT m₁ C mq F Ⓡ (a) If a horizontal force of 1.33 x 10² N is exerted on the block m₂ in the positive x-direction, use the system approach to find the acceleration (in m/s²) of the two blocks. m/s²

Physics for Scientists and Engineers
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Chapter3: Vectors
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A block of mass m1 = 16.4 kg is on a frictionless table to the left of a second block of mass m2 = 17.7 kg, attached by a horizontal string (see the figure below).
HINT
Two masses, m1 and m2, are placed on a horizontal surface such that they do not touch and m1 is to the left of m2. The left and right ends of a string are, respectively, attached to m1 and m2. A horizontal rightward arrow labeled vector F extends from m2.
(a)
If a horizontal force of 1.33 ✕ 102 N is exerted on the block m2 in the positive x-direction, use the system approach to find the acceleration (in m/s2) of the two blocks.
m/s2
(b)
What is the tension (in N) in the string connecting the blocks?
N

 

A block of mass m₁
HINT
=
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16.4 kg is on a frictionless table to the left of a second block of mass m₂ = 17.7 kg, attached by a horizontal string (see the figure below).
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m1
(a) If a horizontal force of 1.33 × 10² N is exerted on the block m₂ in the positive x-direction, use the system approach to find the acceleration (in m/s²) of the two blocks.
m/s²
(b) What is the tension (in N) in the string connecting the blocks?
N
m2
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F
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Transcribed Image Text:A block of mass m₁ HINT = Need Help? 16.4 kg is on a frictionless table to the left of a second block of mass m₂ = 17.7 kg, attached by a horizontal string (see the figure below). Submit Answer m1 (a) If a horizontal force of 1.33 × 10² N is exerted on the block m₂ in the positive x-direction, use the system approach to find the acceleration (in m/s²) of the two blocks. m/s² (b) What is the tension (in N) in the string connecting the blocks? N m2 Read It F Watch It
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