Paralelaxis theorem)= 0.108mIsaいd ニSphereMR?しR-0.1og。A bowling ball of mass 7.1 kg and diameter 21.6 am is thrown down the alley at a speed of 8.7 m/s. Thebowling ball is initially skidding, with no angular velocity, down the alley. The coefficient of frictionbetween the ball and the alley is (0.30, 0.25).Motion InformationEvent 1:1Free-Body DiagramEvent 2:re byl!t, =012 =いitroa* Sipi.12 =02 =0, =V; = 8,7mls01 = 0V2 =02 =aj =KFaz =a2 =aj =Mathematical AnalysisV½ =WqRt Cond,i tionof event 2untilthen, The FBD aboveis vali?, and ball AiCcedernting2 EF=- "F = Mamg = ma> a= -Meg* MRG: EF:0 :f - mg F:mga £ Roc5 MM g%3D%3D=>2R Calculate%3DVz = V, + a€zthe rest is easySolve for te...

Since you have posted this question for the solution of t2 (as mentioned), we have solved that part…

A bowling ball of mass 7.1 kg and diameter 21.6 am is thrown down the alley at a speed of 8.7 m/s. The bowling ball is initlally skidding, with no angular velocity, down the alley. The coefficient of friction between the ball and the alley is (0.30, 0.25). MK

A bowling ball of mass 7.1 kg and diameter 21.6 am is thrown down the alley at a speed of 8.7 m/s. The bowling ball is initlally skidding, with no angular velocity, down the alley. The coefficient of friction between the ball and the alley is (0.30, 0.25). MK

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter8: Rotational Equilibrium And Rotational Dynamics

Section: Chapter Questions

Problem 66P: A particle of mass 0.400 kg is attached to the 100-cm mark of a meter stick of mass 0.100 kg. The...

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Torque

Torque is the rotational equivalent of linear force in physics and mechanics. Based on the course of study, it is also known as the moment of force, rotational force, or turning effect.

Question

Paralel
axis theorem)
= 0.108m
Isaいd ニ
Sphere
MR?
しR-0.1og。
A bowling ball of mass 7.1 kg and diameter 21.6 am is thrown down the alley at a speed of 8.7 m/s. The
bowling ball is initially skidding, with no angular velocity, down the alley. The coefficient of friction
between the ball and the alley is (0.30, 0.25).
Motion Information
Event 1:1
Free-Body Diagram
Event 2:
re byl!
t, =0
12 =
いitroa* Sipi.
12 =
02 =
0, =
V; = 8,7mls
01 = 0
V2 =
02 =
aj =
KF
az =
a2 =
aj =
Mathematical Analysis
V½ =WqRt Cond,i tionof event 2
untilthen, The FBD aboveis vali?, and ball AiCcedernting
2 EF=- "F = Mamg = ma> a= -Meg
* MR
G: EF:0 :f - mg F:mg
a £ Roc
5 MM g
%3D
%3D
=>
2
R Calculate
%3D
Vz = V, + a€z
the rest is easy
Solve for te...
<d <の

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