A- Calculate the equivalent weight and normality of H,PO, for a solution of 6 M H,POgiven the following reactions:(a) H₂PO (aq) + 3OH(aq)(b) H₂PO4(aq) + 2NH3 (aq)PO, ³(aq) + 3H₂O(0)HPO, (aq) + 2NH₂ (aq)H₂PO4 + HF(aq)(c) H₂PO₂(aq) + F(aq)(The atomic weight of O=16, H=1, P= 31).

We have to find normality and molarity.

A- Calculate the equivalent weight and normality of H,PO, for a solution of 6 M H,PO, given the following reactions: (a) H₂PO,(aq) + 3OH(aq) (b) H₂PO,(aq) + 2NH, (aq) PO, (aq) + 3H₂O(l) HPO, ³(aq) + 2NH, (aq) H₂PO+HF(aq) (c) H₂PO₂(aq) + F(aq) (The atomic weight of O=16, H=1, P= 31).

A- Calculate the equivalent weight and normality of H,PO, for a solution of 6 M H,PO, given the following reactions: (a) H₂PO,(aq) + 3OH(aq) (b) H₂PO,(aq) + 2NH, (aq) PO, (aq) + 3H₂O(l) HPO, ³(aq) + 2NH, (aq) H₂PO+HF(aq) (c) H₂PO₂(aq) + F(aq) (The atomic weight of O=16, H=1, P= 31).

Introduction to General, Organic and Biochemistry

11th Edition

ISBN:9781285869759

Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Chapter6: Solutions And Colloids

Section: Chapter Questions

Problem 6.50P

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Concept explainers

Potentiometric Titrations

Potentiometric titration is one of the important titration methods and is mainly carried out to characterize acid solutions. It follows a method similar to that of the normal titration technique, but the main difference is that there is no indicator used in the potentiometric titrations. Instead of using an indicator, electrodes are employed for monitoring the whole titration process. A scientist named Robert Behrend did the potentiometric titration for the first time, and it was done using the mercurous solution and potassium chloride.

Question

A- Calculate the equivalent weight and normality of H,PO, for a solution of 6 M H,PO
given the following reactions:
(a) H₂PO (aq) + 3OH(aq)
(b) H₂PO4(aq) + 2NH3 (aq)
PO, ³(aq) + 3H₂O(0)
HPO, (aq) + 2NH₂ (aq)
H₂PO4 + HF(aq)
(c) H₂PO₂(aq) + F(aq)
(The atomic weight of O=16, H=1, P= 31).

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