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a) Calculate the K for this reaction: 2Fe ag) + Pd* + Pd*2, (aq) * 2Fe*3, + Pd (aq) b) Calculate the equilibrium concentrations, if the above all start at 2.00M.

a) Calculate the K for this reaction: 2Fe ag) + Pd* + Pd*2, (aq) * 2Fe*3, + Pd (aq) b) Calculate the equilibrium concentrations, if the above all start at 2.00M.

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.72PAE
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1. Use the Electromotive chart below to answer parts A&B. Please show all work, thank you!!:)
Electromotive Reaction Table Element E'(volts) Half Reaction Lithium Potassium Barium. Strontium Calcium. Sodium .. 3.045 2.925 .2.90 .2.89 :2.87 .2.714 .2.37 .1.66 1.18 .0.763 .0.74 .0.51 ..0.440 .0.403 .0.3363 .0.277 0.250 0.136 .0.126 0.000 -0.152. -0.2475 -0.32 -0.337 .-0.45: -0.521 .-0.5355 .-0.771' .-0.7991 -0.920 Li Li + le- .K = K* + 1e- Ba = Ba² + 2e- .Sr = Sr² + 2e- Ca = Ca³ + 2e- Na = Na + le- Magnesium Aluminum. Manganese. Zinc ... Chromium .... Phosphorus Iron II Cadmium Thailium Cobalt. Nickel Tin Lead. Hydrogen Antimony.. Arsenic . Bismuth. .Mg = Mg- + 2e- Al = Al+3 + 3e- Mn = Mn +2e- Zn = Zn² + 2e- Cr = Cr + 3e- P+ 2H,0 = 3H,PO, + H* + 1e- Fe = Fe + 2e- Cd = Cd2 + 2e- TI = TI + 1e- Co = Co +2e- Ni = Ni +2e- Sn Sn + 2e- Pb = Pb•² + 2e- Copper II. Gulfur/Sulfurous Acid. Copper I. Iodide. Iron III Silver Mercury Palladium Bromine. Oxygen/Water Chlorine Gold .. Oxygen/Ozone Flourine H = 2H* + 2e- 2Sb + 3H,0 = Sb,O, +6H* + 6e- As + 2H,Ó = HASO, +3H¯ + 3e- Bi + H,Ó = BiO* + 2H* + 3e- Cu = Cu² + 2e- .S+3H,0 = H,SO; + 4H: +4e- Cu = Cu* + 1e- .21- = L, + 2e- Fe = Fe + 1e- Ag = Ag* +1e- .Hg,² = 2H&² + 2e- Pd = Pd+2 + 2e- 2Br- = Br, + 2e- 2H,0 = 0, + 4H* + 4e- 2CI = CL + 2e- Au = Au + 3e- O, + H,O = 0,+ 2H* + 2e- .2F = F, + 2e- .-0.987 -1.066 .-1.229 -1.3595 :-1.50 -2.07 -2.85 Turch
Transcribed Image Text:Electromotive Reaction Table Element E'(volts) Half Reaction Lithium Potassium Barium. Strontium Calcium. Sodium .. 3.045 2.925 .2.90 .2.89 :2.87 .2.714 .2.37 .1.66 1.18 .0.763 .0.74 .0.51 ..0.440 .0.403 .0.3363 .0.277 0.250 0.136 .0.126 0.000 -0.152. -0.2475 -0.32 -0.337 .-0.45: -0.521 .-0.5355 .-0.771' .-0.7991 -0.920 Li Li + le- .K = K* + 1e- Ba = Ba² + 2e- .Sr = Sr² + 2e- Ca = Ca³ + 2e- Na = Na + le- Magnesium Aluminum. Manganese. Zinc ... Chromium .... Phosphorus Iron II Cadmium Thailium Cobalt. Nickel Tin Lead. Hydrogen Antimony.. Arsenic . Bismuth. .Mg = Mg- + 2e- Al = Al+3 + 3e- Mn = Mn +2e- Zn = Zn² + 2e- Cr = Cr + 3e- P+ 2H,0 = 3H,PO, + H* + 1e- Fe = Fe + 2e- Cd = Cd2 + 2e- TI = TI + 1e- Co = Co +2e- Ni = Ni +2e- Sn Sn + 2e- Pb = Pb•² + 2e- Copper II. Gulfur/Sulfurous Acid. Copper I. Iodide. Iron III Silver Mercury Palladium Bromine. Oxygen/Water Chlorine Gold .. Oxygen/Ozone Flourine H = 2H* + 2e- 2Sb + 3H,0 = Sb,O, +6H* + 6e- As + 2H,Ó = HASO, +3H¯ + 3e- Bi + H,Ó = BiO* + 2H* + 3e- Cu = Cu² + 2e- .S+3H,0 = H,SO; + 4H: +4e- Cu = Cu* + 1e- .21- = L, + 2e- Fe = Fe + 1e- Ag = Ag* +1e- .Hg,² = 2H&² + 2e- Pd = Pd+2 + 2e- 2Br- = Br, + 2e- 2H,0 = 0, + 4H* + 4e- 2CI = CL + 2e- Au = Au + 3e- O, + H,O = 0,+ 2H* + 2e- .2F = F, + 2e- .-0.987 -1.066 .-1.229 -1.3595 :-1.50 -2.07 -2.85 Turch
1) a) Calculate the K for this reaction: 2Fe*2 (aq) + Pd*2, (aq) 2Fe"(aq) +3 + Pd b) Calculate the equilibrium concentrations, if the above all start at 2.00M.
Transcribed Image Text:1) a) Calculate the K for this reaction: 2Fe*2 (aq) + Pd*2, (aq) 2Fe"(aq) +3 + Pd b) Calculate the equilibrium concentrations, if the above all start at 2.00M.
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