A car travels 12km due west, 15km due south and 45 km in a direction 50° north of east. Calculate the magnitude and direction of his resultant displacement. O The sum of the X components (X) is = km (1) The sum of the Y components (ZV) is = km (Hi) The magnitude of the resultant displacement is km (iv) The direction (angle) of the resultant displacement (in degrees) is = North of East

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter1: Introduction And Vectors
Section: Chapter Questions
Problem 44P: Three displacement vectors of a croquet ball are shown in Figure P1.44, where |A|=20.0units,...
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A car travels 12km due west, 15km due south and 45 km in a direction 50° north of east. Calculate the magnitude and direction of his resultant
displacement.
) The sum of the X components (ZX) is =
km
(ii) The sum of the Y components (EY) is =
km
(iii) The magnitude of the resultant displacement is =
km
(iv) The direction (angle) of the resultant displacement (in degrees) is =
North of East
Transcribed Image Text:A car travels 12km due west, 15km due south and 45 km in a direction 50° north of east. Calculate the magnitude and direction of his resultant displacement. ) The sum of the X components (ZX) is = km (ii) The sum of the Y components (EY) is = km (iii) The magnitude of the resultant displacement is = km (iv) The direction (angle) of the resultant displacement (in degrees) is = North of East
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