A car travels 12km due west, 15km due south and 45 km in a direction 50° north of east. Calculate the magnitude and direction of his resultant displacement. () The sum of the X components (EX) is = km (1I) The sum of the Y components (ZY) is = km (iii) The magnitude of the resultant displacement is = km (Iv) The direction (angle) of the resultant displacement (in degrees) is = North of East

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter3: Vectors
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Part C Long Answer question (4 x 0.75 = 3 Marks)
A car travels 12km due west, 15km due south and 45 km in a direction 50° north of east. Calculate the magnitude and direction of his
resultant displacement.
() The sum of the X components (2X) is =
km
(i) The sum of the Y components (ZY) is =
km
(iii) The magnitude of the resultant displacement is =
km
(iv) The direction (angle) of the resultant displacement (in degrees) is
°, North of East
Transcribed Image Text:Part C Long Answer question (4 x 0.75 = 3 Marks) A car travels 12km due west, 15km due south and 45 km in a direction 50° north of east. Calculate the magnitude and direction of his resultant displacement. () The sum of the X components (2X) is = km (i) The sum of the Y components (ZY) is = km (iii) The magnitude of the resultant displacement is = km (iv) The direction (angle) of the resultant displacement (in degrees) is °, North of East
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