A cart of mass 8.00 kg was moved by applying two constant forces. Force 1 is 28.0 N at 42.0°, and Force 2 is 13.0 N at 110°. Initially, the cart has a velocity of (3.50 i +2.20 j) m/s. d. What is the acceleration of the cart? Ans. ä = (2.05 i + 3.87 j) or 4.38 e. What is the cart's velocity after 5.00 s? Ans. i = (13.75 i + 21.55 j)" or 25.56" f. What is the position of the cart after 5.00 s? † = 43.125i + 59.375j or73.38 m

A cart of mass 8.00 kg was moved by applying two constant forces. Force 1 is 28.0 N at 42.0°, and Force 2 is 13.0 N at 110°. Initially, the cart has a velocity of (3.50 i +2.20 j) m/s. d. What is the acceleration of the cart? Ans. ä = (2.05 i + 3.87 j) or 4.38 e. What is the cart's velocity after 5.00 s? Ans. i = (13.75 i + 21.55 j)" or 25.56" f. What is the position of the cart after 5.00 s? † = 43.125i + 59.375j or73.38 m

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter5: The Laws Of Motion

Section: Chapter Questions

Problem 5.8P: (a) A cat with a mass of 850 kg in moving to the right with a constant speed of 1.44 m/s. What is...

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