A 200 kg man rides in an elevator while standing on a scale. As the elevator rises with a constant acceleration of 6m/s2, what is the reading of the scale? b) As the elevator lowers itself with a constant acceleration of 6m/s2, what is the reading of the scale? c) As the elevator rises with a constant velocity of 2m/s, what is the reading of the scale?

A 200 kg man rides in an elevator while standing on a scale. As the elevator rises with a constant acceleration of 6m/s2, what is the reading of the scale? b) As the elevator lowers itself with a constant acceleration of 6m/s2, what is the reading of the scale? c) As the elevator rises with a constant velocity of 2m/s, what is the reading of the scale?

Name: A 200 kg man rides in an elevator while standing on a scale. As the el
Uploaded: 2024-03-20T06:57:57.000Z
Channel: Bartleby
Description: A 200 kg man rides in an elevator while standing on a scale. As the elevator rises with a constant acceleration of 6m/s2, what is the reading of the scale? b) As the elevator lowers itself with a constant acceleration of 6m/s2, what is the reading of

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter4: The Laws Of Motion

Section: Chapter Questions

Problem 57P: A car accelerates down a hill (Fig. P4.57), going from rest to 30.0 m/s in 6.00 s. A toy inside the...

See similar textbooks

Similar questions

A car accelerates down a hill (Fig. P4.57), going from rest to 30.0 m/s in 6.00 s. A toy inside the car hangs by a string from the cars ceiling. The ball in the figure represents the toy, of mass 0.100 kg. The acceleration is such that the string remains perpendicular to the ceiling. Determine (a) the angle and (b) the tension in the string. Figure P4.57
Review. A block of mass m = 2.00 kg is released from rest at h = 0.500 m above the surface of a table, at the top of a = 30.0 incline as shown in Figure P4.53. The frictionless incline is fixed on a table of height H = 2.00 m. (a) Determine the acceleration of the block as it slides down the incline. (b) What is the velocity of the block as it leaves the incline? (c) How far from the table will the block hit the floor? (d) What time interval elapses between when the block is released and when it hits the floor? (e) Does the mass of the block affect any of the above calculations? Figure P4.53 Problems 53 and 59
/ A 50.0?? woman inside an elevator is standing on a scale. How will the acceleration of the elevator affect the scale reading? Calculate the scale reading when (a) the elevator is accelerating upward at ay=3.0 m/s2, (b) the elevator is going up with a constant velocity of vy=2.0 m/s, (c) the elevator is at rest, (d) the elevator is going down with acceleration ay=-3.0 m/s2, and (e) the elevator is going down with a constant velocity vy= -2.0 m/s.
A 60 kg person stands on a scale in an elevator. How many Newtons does the scale read: a) when the elevator is ascending with an acceleration of 1 m/s2? b) when the elevator is descending with an acceleration of 1 m/s2? c) when the elevator is ascending at a constant speed of 3 m/s?
An elevator packed with people has a mass of 1950 kg. 1) The elevator accelerates upward (in the positive direction) from rest at a rate of 1.9 m/s2 for 2.3 s. Calculate the tension in the cable supporting the elevator in newtons. 2) The elevator continues upward at constant velocity for 8.3 s. What is the tension in the cable, in newtons, during this time? 3)The elevator experiences a negative acceleration at a rate of 0.45 m/s2 for 2.1 s. What is the tension in the cable, in newtons, during this period of negative acceleration? 4)
An elevator loaded with tourists has a mass of 1750 kg. a.) The elevator accelerates upward (in the positive direction) from rest at a rate of 1.55 m/s2 for 2.3 s. Calculate the tension in the cable supporting the elevator in newtons b.) The elevator continues upward at constant velocity for 8.5 s. What is the tension in the cable, in Newtons, during this time? c.) The elevator experiences a negative acceleration at a rate of 0.65 m/s2 for 2.6 s. What is the tension in the cable, in Newtons, during this period of negative accleration? d.) How far, in meters, has the elevator moved above its original starting point?
To confirm what the student learned in a physics class, a student takes a bathroom scale into an elevator and places it on the floor of the elevator. The student steps onto the scale while the elevator accelerates upward. Determine the scale reading if the student has a mass of 60.0 kg and the smart phone app measures the acceleration to be 4.90m/s^2 , what is the reading on the scale? a. 147 N b. 588 N c. 882 N d. 294 N
1. A 500.0 N student standing on a scale in an elevator notices that the scale reads 550.0 N. a. From this information, the student knows that the elevator’s acceleration isA) upward.B) downward.C) The student cannot tell whether the elevator is accelerating upward or downward.b. From this information, the student knows that the elevator’s velocity isD) upward.E) downward.F) The student cannot tell whether the elevator is moving upward or downward.2. You swing a bat and hit a heavy box with a force of 1600 N. a. If the box moves when you hit it, the force the box exerted on the bat when hit isA) greater than 1600 N if the bat bounces back.B) greater than 1600 N.C) exactly 1600 N.D) less than 1600 N *please write a detail as much as possible for both question
The coefficient of static friction between the tires of a car and a horizontal road is 0.2. If the net force on the car is the force of static friction exerted by the road, what is the maximum acceleration of the car when it is braked? The acceleration clue to gravity is 9.81 m/s^2 . Answer in units of m/s^2. What is the shortest distance in which the car can stop if it is initially traveling at 30 m/s? Answer in units of m.
Q1/ A 50.0kg woman inside an elevator is standing on a scale. How will the acceleration of the elevator affect the scale reading? Calculate the scale reading when (a) the elevator is accelerating upward at a-3.0 m/s², (b) the elevator is going up with a constant velocity of v, -2.0 m/s, (c) the elevator is at rest, (d) the elevator is going down with acceleration a--3.0 m/s², and (e) the elevator is going down with a constant velocity v= -2.0 m/s.
A model rocket is fired vertically from rest. It has a constant acceleration of 21.9 m/s^2 for the first 1.50 s. Then the fuel is exhausted, and it is in free fall. The rocket has a mass of 99.8 g, the mass of the fuel is much less than 99.8 g (I.e. ignore the mass of the fuel). Ignore air resistance. (a) Calculate how high does the rocket travel. (b) how long after lift-off does the rocket return to the ground.
An elevator cabin has a mass of 380 kg, and the combined mass of the people inside the cabin is 180 kg. The cabin is pulled upward by a cable, in which there is a tension force of 7600 N. What is the acceleration of the elevator? a. 3.76 m/s2 c. 3.76 m/s2 b. 3.76 m/s2 d. 3.76 m/s2