A certain kind of sheet metal has an average of 7 defects per 12 ft². Assuming a Poisson distribution, we will want to find the probability that a 20 ft2 piece of sheet metal has at least 9 defects. (a) First find the mean number of defects per 20 ft² of this sheet metal. Give your answer as a fraction 3/ defects then you would type "3/4" in the with no units (for example, if you find the mean to be (defe 4 20 ft² answer box). fl= defects 20 ft² ft²"), (b) Then find the probability that a 20 ft2 piece of this sheet metal has at least 9 defects. Round this answer to 4 places after the decimal point, if necessary. P(at least 9 defects) =

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A certain kind of sheet metal has an average of 7 defects per 12 ft2. Assuming a Poisson distribution, we
will want to find the probability that a 20 ft² piece of sheet metal has at least 9 defects.
(a) First find the mean number of defects per 20 ft² of this sheet metal. Give your answer as a fraction
3
defects
then you would type "3/4" in the
20 ft²
with no units (for example, if you find the mean to be
4
answer box).
μ =
defects
20 ft²
(b) Then find the probability that a 20 ft2 piece of this sheet metal has at least 9 defects. Round this
answer to 4 places after the decimal point, if necessary.
P(at least 9 defects)
Transcribed Image Text:A certain kind of sheet metal has an average of 7 defects per 12 ft2. Assuming a Poisson distribution, we will want to find the probability that a 20 ft² piece of sheet metal has at least 9 defects. (a) First find the mean number of defects per 20 ft² of this sheet metal. Give your answer as a fraction 3 defects then you would type "3/4" in the 20 ft² with no units (for example, if you find the mean to be 4 answer box). μ = defects 20 ft² (b) Then find the probability that a 20 ft2 piece of this sheet metal has at least 9 defects. Round this answer to 4 places after the decimal point, if necessary. P(at least 9 defects)
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