A certain signal molecule S in muscle tissue is degraded by two different biochemical pathways: when only Path 1 is active, the half-life of S is 6.6 s. When only Path 2 is active, the half-life of S is 104. s. Calculate the half-life of S when both pathways are active. Be sure your answer has the correct number of significant digits. 0$ X S Een olo

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Chapter11: Rate Of Reaction
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Solving applied problems with first-order kinetics
s
A certain signal molecule S in muscle tissue is degraded by two different biochemical pathways: when only Path 1 is active, the half-life of S is 6.6 s. When only
Path 2 is active, the half-life of S is 104. s. Calculate the half-life of S when both pathways are active.
Be sure your answer has the correct number of significant digits.
Explanation
Check
JUL
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Transcribed Image Text:Solving applied problems with first-order kinetics s A certain signal molecule S in muscle tissue is degraded by two different biochemical pathways: when only Path 1 is active, the half-life of S is 6.6 s. When only Path 2 is active, the half-life of S is 104. s. Calculate the half-life of S when both pathways are active. Be sure your answer has the correct number of significant digits. Explanation Check JUL 16 0.0 X 5 9 S tv W 1/5 MacBook Air Hunter V BE7 Ⓒ2023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility olo Ar 4
|||
ALEKS Canvas CSU
OKINETICS AND EQUILIBRIUM
Writing the rate law implied by a simple mechanism
elementary reaction
Write the balanced
chemical equation for the
overall chemical reaction:
1 (CH3), CBr(aq)
(CH3)₂C (aq) + Br (aq)
2 (CH3)₂C (aq) + OH¯(aq) →
(CH3)₂C
k₂
Suppose also k₁k₂. That is, the first step is much faster than the second.
Write the experimentally-
observable rate law for the
overall chemical reaction.
Note: your answer should
not contain the
concentrations of any
intermediates.
Express the rate constant
k for the overall chemical
reaction in terms of K₁, K₂,
and (if necessary) the rate
constants k.₁ and k-2 for
1
the reverse of the two
elementary reactions in
Explanation
Check
-
00
rate = k
k =
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COH(aq)
A ALEKS-Hunter Stephens - Learn
rate constant
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k₁
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KOH Solution pH: 12.58
0/5
Hunter
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© 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accessibility
S
Transcribed Image Text:||| ALEKS Canvas CSU OKINETICS AND EQUILIBRIUM Writing the rate law implied by a simple mechanism elementary reaction Write the balanced chemical equation for the overall chemical reaction: 1 (CH3), CBr(aq) (CH3)₂C (aq) + Br (aq) 2 (CH3)₂C (aq) + OH¯(aq) → (CH3)₂C k₂ Suppose also k₁k₂. That is, the first step is much faster than the second. Write the experimentally- observable rate law for the overall chemical reaction. Note: your answer should not contain the concentrations of any intermediates. Express the rate constant k for the overall chemical reaction in terms of K₁, K₂, and (if necessary) the rate constants k.₁ and k-2 for 1 the reverse of the two elementary reactions in Explanation Check - 00 rate = k k = JUL 16 COH(aq) A ALEKS-Hunter Stephens - Learn rate constant tv www-awu.aleks.com k₁ W MacBook Air ローロ 00 X 98 KOH Solution pH: 12.58 0/5 Hunter n Ar © 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accessibility S
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