A charged particle ( m = 5.0 g, q = -90 µC) moves horizontally at a constant speed of 30 km/s in a region where the 2 free-fall gravitational acceleration is 9.8 m/s – downward, the electric field is 700 N/C upward, and the magnetic field is perpendicular to the velocity of the particle. What is the magnitude of the magnetic field in this region? a. 75 mT

Principles of Physics: A Calculus-Based Text
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Chapter22: Magnetic Forces And Magnetic Fields
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A charged particle ( m = 5.0 g, q =-90 µC) moves horizontally at a constant speed of 30 km/s in a region where the
free-fall gravitational acceleration is 9.8 m/s - downward, the electric field is 700 N/C upward, and the magnetic field
is perpendicular to the velocity of the particle. What is the magnitude of the magnetic field in this region?
O a. 75 mT
%3!
2
b.41 mT
C. 37 mT
63 mT
e. 112 mT
Transcribed Image Text:A charged particle ( m = 5.0 g, q =-90 µC) moves horizontally at a constant speed of 30 km/s in a region where the free-fall gravitational acceleration is 9.8 m/s - downward, the electric field is 700 N/C upward, and the magnetic field is perpendicular to the velocity of the particle. What is the magnitude of the magnetic field in this region? O a. 75 mT %3! 2 b.41 mT C. 37 mT 63 mT e. 112 mT
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