A chemist has 70.0 mL of a 16.0 M solution of HCl. He dilutes the acid with water to make ithave a molarity of 10.0 M. What is the new volume of the acid? Equations- M = mol of solute /L of solution for molarity M 1 (V 1 ) = M 2 (V 2 ) for dilution

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Problem 12.138QP: An aqueous solution is 20.0% by mass of sodium thiosulfate pentahydrate, Na2S2O35H2O. What is the...
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A chemist has 70.0 mL of a 16.0 M solution of HCl. He dilutes the acid with water to make it
have a molarity of 10.0 M. What is the new volume of the acid?

Equations- M = mol of solute /L of solution for molarity

M 1 (V 1 ) = M 2 (V 2 ) for dilution

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