A chemist received a report from an analysis involving the iron-phenanthroline method, containing the calibration curve for Fe standards (20 ppm, 30 ppm, 40 ppm, 50 ppm, and 60 ppm) and their corrected absorbances. The report stated that the equation of the line and r2 were as follows: y = 0.015066 x – 0.154424 r2 = 0.9997 The sample they tested gave a corrected reading of 0.417. How much Fe is present in ppm? 2.80 17.43 2.60 37.93
A chemist received a report from an analysis involving the iron-phenanthroline method, containing the calibration curve for Fe standards (20 ppm, 30 ppm, 40 ppm, 50 ppm, and 60 ppm) and their corrected absorbances. The report stated that the equation of the line and r2 were as follows: y = 0.015066 x – 0.154424 r2 = 0.9997 The sample they tested gave a corrected reading of 0.417. How much Fe is present in ppm? 2.80 17.43 2.60 37.93
Chapter8: Sampling, Standardization, And Calibration
Section: Chapter Questions
Problem 8.23QAP
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A chemist received a report from an analysis involving the iron-phenanthroline method, containing the calibration curve for Fe standards (20 ppm, 30 ppm, 40 ppm, 50 ppm, and 60 ppm) and their corrected absorbances. The report stated that the equation of the line and r2 were as follows:
y = 0.015066 x – 0.154424
r2 = 0.9997
The sample they tested gave a corrected reading of 0.417. How much Fe is present in ppm?
-
2.80
-
17.43
-
2.60
-
37.93
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