A chemistry student weighs out 0.0623 g of acrylic acid (HCH,CHCO,) into a 250. mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1400 M NAOH solution. Calculate the volume of NaOH solution the student will need to add to reach the equivalence point. Round your answer to 3 significant digits.

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter1: The Nature Of Chemistry
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A chemistry student weighs out 0.0623 g of acrylic acid (HCH,CHCO,) into a 250. mL volumetric flask and dilutes to the mark with distilled
water. He plans to titrate the acid with 0:1400 M NaOH solution.
Calculate the volume of NaOH solution the student will need to add to reach the equivalence point. Round your answer to 3 significant digits.
Transcribed Image Text:A chemistry student weighs out 0.0623 g of acrylic acid (HCH,CHCO,) into a 250. mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0:1400 M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the equivalence point. Round your answer to 3 significant digits.
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Step 1

Given: The mass of acrylic acid added to 250 mL of the volumetric flask is 0.0623 g. The molarity of NaOH solution is 0.1400 M.

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