A child bounces in a harness suspended from a door frame by three elastic bands. (a) If each elastic band stretches 0.290 m while supporting a 7.75-kg child at rest, what is the force constant for each elastic band? Assume that each spring supports 1/3 of the child's weight.  N/m (b) What is the time for one complete bounce of this child?  s (c) What is the child's maximum velocity if the amplitude of her bounce is 0.290 m?

Q: A 0.31-kg glider is attached to a horizontal spring with stiffness of 135 N/m. If the equilibrium…

A: In the given question, we have to determine the acceleration at 0.09m.

Q: A 3 kg mass is suspended from a spring with k = 80 N/m. What will be the stretch in the spring? O A)…

A:

Q: A 2.35-kg uniform bar oflength l = 1.30 m is heldin a horizontal position bythree vertical springs…

A: a)Weight of the bar = mxg = 2.35×9.8 = 23.03 N

Q: A horizontal spring with force constant k = 58.0 N/m is used to accelerate a 0.520-kg mass on a…

A: Write the given values with the suitable variables. k=58 N/mm=0.52 kgx=5.75×10-2 m Here, k is the…

Q: A 4.020-gram bullet is projected horizontally to a block of timber that rest on a horizontal floor.…

A:

Q: When you hang a 100 g mass from a spring, the spring stretches 2 cm. If you remove the 100 g mass…

A:

Q: 3.45-g bullet embeds itself in a 1.67-kg block, which is attached to a spring of force constant 785…

A:

Q: In a spring block system the position is given by x (t) = (7.40 cm) cos (4.16t - 2.42). Determine…

A: a. the position at t=1 s is x=0.074 mcos4.161 s-2.42=0.0739 m

Q: A 0.51-kg block attached to a spring with force constant 140 N/m is free to move on a frictionless,…

A: (a) Calculate the magnitude of force on the block. |Fs|=kx Here, k is the spring constant and x is…

Q: A 4.020-gram bullet is projected horizontally to a block of timber that rest on a horizontal floor.…

A: Mass of bullet: m = 4.020 g = 4.020 x 10-3 kg Maximum displacement of the block: x = 0.0035 m Spring…

Q: A block with weight w = end of a vertical spring with a spring constant k. The spring is stretched…

A:

Q: A 10 Kg object hangs at rest from a spring with force constant 180 N/m. A 15 Kg object is gently…

A:

Q: When you hang a 100 g mass from a spring, the spring stretches 2 cm. If you remove the 100 g mass…

A: Given data: Known Mass (m1) = 100 g = 0.100 kg Stretch in spring (x1) = 2 cm = 0.02 m Unknown mass =…

Q: 1.2 kg A spring of spring constant k is hung from a horizontal support. A block of mass m = 1.2 kg…

A: Given quantities: mass of the block (m) = 1.2 kg acceleration due to gravity (g) = 10 m/s2…

Q: A spring has a length of 0.210 m when a 0.300 kg mass hangs from it, and a length of 0.750 m when a…

A: Given:   The length of the spring is 0.210 m when 0.300 kg mass is hangs from it. The length of the…

Q: To use the equations of equilibrium to analyze a system containing a wedge and to determine the…

A: Using spring combo Value of p= 397 N

Q: What mass must be added to a spring with k = 80 N/m to stretch the spring 15.0 cm? O A) 1200 kg B)…

A: Given data: Spring constant is, k=80 N/m. Stretching distance is, x=15.0 cm=0.15 m.

Q: A pendulum consists of a 2 kg bob attached to a light string of length 6.0 m.  The bob is struck…

A:

Q: A 9.3 kg mass is attached to a spring, k = 123.1 N/m, so it can oscillate horizontally without…

A: Write the given values with the suitable variables. m=9.3 kgk=123.1 N/mx0=7 cm=0.07 mv0=20 cm/s=0.2…

Q: A 1.00-kg glider attached to a spring with a force constant 9.0 N/m oscllates on a frictionless,…

A:

Q: The system is released from rest with no slack in the cable and with the spring stretched 190 mm.…

A: Given : Mass of cart = 11 kg Stretched spring = 190 mm

Q: A child’s toy consists of plastic attached to a spring. The spring is compressed against the floor…

A:

Q: A 0.200 kg object is attached to a horizontal spring with a spring constant of 77.0 N/m. The other…

A: Given : m = 0.200 kg k = 77 N/m F = 10 N

Q: A 0.60-kg block attached to a spring with force constant 130 N/m is free to move on a frictionless,…

A: Given:- The spring constant k = 130 N/m  mass of the block m = 0.60 kg  The blocks is released from…

Q: You are on a pogo stick bouncing up and down. (If you don’t know what a pogo stick is, please ask…

A:

Q: A mass hanging from a spring is set in motion and its ensuing velocity is given by v(t) = - 4t sin…

A: The equation of velocity :v(t) = - 4πsin πt s(0) = 4

Q: A meterstick (L = 1 m) has a mass of m = 0.155 kg. Initially it hangs from two short strings: one at…

A:

Q: **13. A 30.0-kg block is rest- ing on a flat horizontal table. On top of this block is resting a…

A:

Q: A scene in a movie has a stuntman falling through a floor onto a bed in the room below. The plan is…

A: Here, the potential energy possessed by the mass at a given height gets converted to spring…

Q: Consider a simple wheelchair with a suspension system (bumper) composed of a spring and a dashpot as…

A: cdd2(y-x)k(y-x)free body diagrammay block Fm=ma=md2ydtv             fk=k(y-x)  fc=cddt(y-x)

Q: ates at the end of an ideal spring with force constant 25.0 N/cm on a frictionless horizontal air…

A: Given:-  The spring constant [ force constant ] k = 25.0 N/cm = 25 x 102 N/m  The acceleration of…

Q: How far has the spring compressed by the time the block first momentarily comes to rest? Assume the…

A:

Q: A 0.200 kg mass attached to the end of a spring causes it to stretch 5.0 cm. If another 0.200 kg…

A: Given data The mass of the object is given as m = 0.200 kg. The stretching distance of the spring is…

Q: A 2.60-kg block is attached to a horizontal spring that has a spring constant of 366 N/m. At the…

A: Given data The mass is m=2.60 kg The spring displacement is x=-0.115 m The spring constant is K=366…

Q: 2. A mass, M, is attached to a massless rod with length, L, to act as a pendulum. The mass is lifted…

A: Energy conservation theorem states that total energy of an isolated system conserves. Energy can…

Q: Why does it hurt more if your hand is snapped with a ruler than with a loose spring, even if the…

A: The ruler is a stiffer system but a loose spring system is not that much stiffer.

Q: A spring is attached to a block with a mass of 2.33 kg. The block is set on a rough horizonal…

A:

Q: A horizontal spring-mass system has low friction, spring stiffness 220 N/m, and mass 0.4 kg. The…

A: Given

Q: object, whose mass is 0.640 kg, is attached to a spring with a force constant of 148 N/m. The object…

A: GivenMass of object,m=0.640 kgSpring constant, k=148 N/mObject is pulled to right a distance,…

Q: A cart of mass 2.0 kg on a horizontal surface is attached to a horizontal spring of negligible mass.…

A:

Q: The force P = 267 N. Determine the magnitude of the steady-state spring compression 6, which is…

A: Given: Cart mass, M=41 kg Slider mass, m=9 kg Force, P=267 N Spring modulus, k=385 N/m Inclined…

Q: The 100 kg block is supported by two springs having the stiffness shown. Determine the stretch of…

A:

Q: A 4.020-gram bullet is projected horizontally to a block of timber that rest on a horizontal floor.…

A: Given that, The mass of a bullet, m = 4.020-gram Initially, the bullet was at rest on a horizontal…

Q: A 2.50-kg uniform bar of length e = 1.30 m is held in a horizontal position by three vertical…

A: Given,

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.