A closed surface with dimensions a=b%3D0.40 m and c=0.60 m is located as in the figure below. The left edge of the closed surface is located at position x= a. The electric field in the region is non-uniform and is given by E=(3.0+ 58x ) i N/C, where x is in meters. Calculate the net electric flux leaving the closed surface?

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Author:Raymond A. Serway, John W. Jewett
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Chapter24: Gauss’s Law
Section: Chapter Questions
Problem 24.63CP: A dosed surface with dimensions a = b= 0.400 111 and c = 0.600 in is located as shown in Figure...
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A closed surface with dimensions a=b%3D0.40 m and c=0.60 m is located as in the figure below. The left edge of the closed
surface is located at position x= a. The electric field in the region is non-uniform and is given by E=(3.0+ 58x² ) i N/C,
where x is in meters. Calculate the net electric flux leaving the closed surface?
y
E
x = a
Select one:
O A. 13.60
OB. 19.40
OC. 5.57
OD. 7.80
OE 1.86
Transcribed Image Text:A closed surface with dimensions a=b%3D0.40 m and c=0.60 m is located as in the figure below. The left edge of the closed surface is located at position x= a. The electric field in the region is non-uniform and is given by E=(3.0+ 58x² ) i N/C, where x is in meters. Calculate the net electric flux leaving the closed surface? y E x = a Select one: O A. 13.60 OB. 19.40 OC. 5.57 OD. 7.80 OE 1.86
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