A closed surface with dimensions a=b=0.40 m and c=0.60 m is located as in the figure below. The left edge of the closed surface is located at position x= a. The electric field in the region is non-uniform and is given by E=(3.0+ 32x2) i N/C, where x is in meters. Calculate the net electric flux leaving the closed surface? E x = a

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
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Chapter6: Gauss's Law
Section: Chapter Questions
Problem 75AP: (a) Calculate the electric flux through the open hemispherical surface due to the electric field E...
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A closed surface with dimensions
a=b=0.40 m and c=0.60 m is located
as in the figure below. The left edge of
the closed surface is located at
position x= a. The electric field in the
region is non-uniform and is given by
E=(3.0+ 32x2 ) i N/C, where x is in
meters. Calculate the net electric
flux leaving the closed surface?
E
Select one:
A. 3.07
В. 7.50
С. 4.30
D. 1.02
E. 10.70
Transcribed Image Text:A closed surface with dimensions a=b=0.40 m and c=0.60 m is located as in the figure below. The left edge of the closed surface is located at position x= a. The electric field in the region is non-uniform and is given by E=(3.0+ 32x2 ) i N/C, where x is in meters. Calculate the net electric flux leaving the closed surface? E Select one: A. 3.07 В. 7.50 С. 4.30 D. 1.02 E. 10.70
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