A closed surface with dimensions a=b%=D0.40 m and c=0.60 m is located as in the figure below. The left edge of the closed surface is located at position x= a. The electric field in the region is non-uniform and is given by E=(3.0+ 44x) i N/C, where x is in meters. Calculate the net electric flux leaving the closed surface? x = a

Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter24: Gauss’s Law
Section: Chapter Questions
Problem 24.63CP: A dosed surface with dimensions a = b= 0.400 111 and c = 0.600 in is located as shown in Figure...
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A closed surface with dimensions a=b=D0.40 m and c=0.60 m is located as in the figure below. The left edge of the closed
surface is located at position x= a. The electric field in the region is non-uniform and is given by E=(3.0+ 44x2 ) i N/C,
where x is in meters. Calculate the net electric flux leaving the closed surface?
b-
Select one:
OA. 5.91
O B. 1.41
OC. 14,71
OD. 4.22
OE 10.31
Transcribed Image Text:A closed surface with dimensions a=b=D0.40 m and c=0.60 m is located as in the figure below. The left edge of the closed surface is located at position x= a. The electric field in the region is non-uniform and is given by E=(3.0+ 44x2 ) i N/C, where x is in meters. Calculate the net electric flux leaving the closed surface? b- Select one: OA. 5.91 O B. 1.41 OC. 14,71 OD. 4.22 OE 10.31
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