A coffee shop currently sells 470 lattes a day at $3.00 each. They recently tried raising the by price by $0.25 a latte, and found that they sold 50 less lattes a day. a) Assume that the number of lattes they sell in a day, N , is linearly related to the sale price, p (in dollars). Find an equation for N as a function of p. N(p) %3D b) Revenue (the amount of money the store brings in before costs) can be found by multiplying the cost per cup times the number of cups sold. Again using p as the sales price, use your equation from above to write an equation for the revenue, R as a function of p . R(p) = %3D c) The store wants to maximize their revenue (make as much money as possible). Find the value of p that will maximize the revenue (round to the nearest cent).
A coffee shop currently sells 470 lattes a day at $3.00 each. They recently tried raising the by price by $0.25 a latte, and found that they sold 50 less lattes a day. a) Assume that the number of lattes they sell in a day, N , is linearly related to the sale price, p (in dollars). Find an equation for N as a function of p. N(p) %3D b) Revenue (the amount of money the store brings in before costs) can be found by multiplying the cost per cup times the number of cups sold. Again using p as the sales price, use your equation from above to write an equation for the revenue, R as a function of p . R(p) = %3D c) The store wants to maximize their revenue (make as much money as possible). Find the value of p that will maximize the revenue (round to the nearest cent).
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter1: Expressions And Functions
Section1.5: Descriptive Modeling And Accuracy
Problem 3BGP
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