A company claims that the mean monthly residential electricity consumption in a certain region is more than 860 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 70 residential customers has a mean monthly consumption of 890 kWh. Assume the population standard deviation is 123 kWh. At α=0.01, can you support the claim? Complete parts (a) through (e). (a) Identify H0 and Ha. Choose the correct answer below. A. H0: μ≤860 Ha: μ>860 (claim) B. H0: μ=890 Ha: μ≠890 (claim) C. H0: μ=860 (claim) Ha: μ≠860 D. H0: μ>860 (claim) Ha: μ≤860 E. H0: μ>890 (claim) Ha: μ≤890 F. H0: μ≤890 Ha: μ>890 (claim) (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical values are ±nothing. B. The critical value is nothing. Identify the rejection region(s). Select the correct choice below. A. The rejection region is z<2.33. B. The rejection regions are z<−2.33 and z>2.33. C. The rejection region is z>2.33. (c) Find the standardized test statistic. Use technology. The standardized test statistic is z=nothing. (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. A. Reject H0 because the standardized test statistic is in the rejection region. B. Reject H0 because the standardized test statistic is not in the rejection region. C. Fail to reject H0 because the standardized test statistic is in the rejection region. D. Fail to reject H0 because the standardized test statistic is not in the rejection region. (e) Interpret the decision in the context of the original claim. At the 1% significance level, there ▼ isis is notis not enough evidence to ▼ support reject the claim that the mean monthly residential electricity consumption in a certain region ▼ is greater than is less than is different from nothing kWh. Click to select your answer(s).
A company claims that the mean monthly residential electricity consumption in a certain region is more than 860 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 70 residential customers has a mean monthly consumption of 890 kWh. Assume the population standard deviation is 123 kWh. At α=0.01, can you support the claim? Complete parts (a) through (e). (a) Identify H0 and Ha. Choose the correct answer below. A. H0: μ≤860 Ha: μ>860 (claim) B. H0: μ=890 Ha: μ≠890 (claim) C. H0: μ=860 (claim) Ha: μ≠860 D. H0: μ>860 (claim) Ha: μ≤860 E. H0: μ>890 (claim) Ha: μ≤890 F. H0: μ≤890 Ha: μ>890 (claim) (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical values are ±nothing. B. The critical value is nothing. Identify the rejection region(s). Select the correct choice below. A. The rejection region is z<2.33. B. The rejection regions are z<−2.33 and z>2.33. C. The rejection region is z>2.33. (c) Find the standardized test statistic. Use technology. The standardized test statistic is z=nothing. (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. A. Reject H0 because the standardized test statistic is in the rejection region. B. Reject H0 because the standardized test statistic is not in the rejection region. C. Fail to reject H0 because the standardized test statistic is in the rejection region. D. Fail to reject H0 because the standardized test statistic is not in the rejection region. (e) Interpret the decision in the context of the original claim. At the 1% significance level, there ▼ isis is notis not enough evidence to ▼ support reject the claim that the mean monthly residential electricity consumption in a certain region ▼ is greater than is less than is different from nothing kWh. Click to select your answer(s).
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
A company claims that the mean monthly residential electricity consumption in a certain region is more than
860
kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of
70
residential customers has a mean monthly consumption of
890
kWh. Assume the population standard deviation is
123
kWh. At
α=0.01,
can you support the claim? Complete parts (a) through (e).(a) Identify
H0
and
Ha.
Choose the correct answer below.H0:
μ≤860
Ha:
μ>860
(claim)H0:
μ=890
Ha:
μ≠890
(claim)H0:
μ=860
(claim)Ha:
μ≠860
H0:
μ>860
(claim)Ha:
μ≤860
H0:
μ>890
(claim)Ha:
μ≤890
H0:
μ≤890
Ha:
μ>890
(claim)(b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology.
(Round to two decimal places as needed.)
The critical values are
±nothing.
The critical value is
nothing.
Identify the rejection region(s). Select the correct choice below.
The rejection region is
z<2.33.
The rejection regions are
z<−2.33
and
z>2.33.
The rejection region is
z>2.33.
(c) Find the standardized test statistic. Use technology.
The standardized test statistic is
z=nothing.
(Round to two decimal places as needed.)
(d) Decide whether to reject or fail to reject the null hypothesis.
Reject
H0
because the standardized test statistic
is
in the rejection region.Reject
H0
because the standardized test statistic
is not
in the rejection region.Fail to reject
H0
because the standardized test statistic
is
in the rejection region.Fail to reject
H0
because the standardized test statistic
is not
in the rejection region.(e) Interpret the decision in the context of the original claim.
At the
enough evidence to
the claim that the mean monthly residential electricity consumption in a certain region
1%
significance level, there
▼
isis
is notis not
▼
support
reject
▼
is greater than
is less than
is different from
nothing
kWh.Click to select your answer(s).
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