A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and other features. The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 52 months and a standard deviation of 4 months. Using the empirical rule (as presented in the book), what is the approximate percentage of cars that remain in service between 56 and 64 months?

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A: We want to find the probability (%) P(49<X<79)= ?  X~N(μ=49,σ2=102)

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A: Here, The bell company manufactures laptop computers. A study indicates that the life spans of their…

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A: Given that, The distribution of the number of phone calls answered each day, Mean = 48 Standard…

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A: The Z-score of a random variable X is defined as follows: Z = (X – µ)/σ. Here, µ and σ are the mean…

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A: Given that, Mean, mu= 11.4 Standard deviation, sigma= 2.7 We know that,  Z score= (X- my)/sigma

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A:

Q: The physical plant at the main campus of a large state university recieves daily requests to replace…

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A: The empirical rule for normal distribution states that 95% of data lies within 2 standard deviations…

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A: Given ROP=350 Formula for the ROP is given by ROP=Demand during lead time+safety stock Hence, Safety…

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A: Use excel formula "=NORM.S.DIST(1.976, TRUE)" to find the probability.

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A: Given,mean(μ)=4.89standard deviation(σ)=0.63sample size(n)=450

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A:

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A: Given  mean of 670 and a standard deviation of 220.

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A: Empirical reules:1)68% of observations falls within the first standard deviation (µ ± σ)2)95% within…

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A: Given that.   X~N( μ , ?^2 )   μ=54     , ?=4   Z-score =( x - μ )/?

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A: Given that, μ=200σ=12

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Q: A company has a policy of retiring company cars; this policy looks at number of miles driven,…

A:

Q: A company has a policy of retiring company cars; this policy looks at number of miles driven,…

A: According to empirical rule, also known as 68-95-99.7 rule.

Q: The physical plant at the main campus of a large state university receives daily requests to replace…

A: Given, The distribution of the number of daily requests is bell shaped with mean of 52 and standard…

Q: In a mid-size company, the distribution of the number of phone calls answered each day by each of…

A: Given: μ=58 & σ = 9  Percentage of calls between 25 and 79 can be obtained by the probability…

Q: im confused on this porblem

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A: The test hypotheses are given below: H0:μ=0 lbsHa:μ>0 lbs From the given information, the…

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A: The 68-95-99.7% (Empirical) Rule: For a normal distribution, the empirical rule (68-95-99.7% Rule)…

Q: In a mid-size company, the distribution of the number of phone calls answered each day by each of…

A: Given information: The distribution of the number of phone calls answered each day is bell-shaped…

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Q: The physical plant at the main campus of a large state university recieves daily requests to replace…

A: Given: μ=63σ=5

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Q: The physical plant at the main campus of a large state university recieves daily requests to replace…

A:

Q: In a mid-size company, the distribution of the number of phone calls answered each day by each of…

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A: Balitmore mean = 286455 sd = 11200 DenverMean = 188468sd = 8230

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A: 72.5 3.1 75 64.3 3.8 70

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Q: A company has a policy of retiring company cars; this policy looks at number of miles driven,…

A: the PDF of normal distribution is = 1/σ * √2π * e ^ -(x-u)^2/ 2σ^2standard normal distribution is a…

Q: The heights of German men are normally distributed with a mean of 67.9 inches and a standard…

A: a) Empirical rule: The probability of the observation lies within 1 standard deviation of the mean,…

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A: We want to test the hypothesis

Q: The physical plant at the main campus of a large state university recieves daily requests to replace…

A: Given that, Mean = 46 Standard deviation = 7