A composite assembly of length, L-375 mm, consisting of a steel (G-77 GPa) core (2) connected by rigid plates at the ends of an aluminum [G-35 GPa) tube (1) is shown. The aluminum tube has outside diameter D₁-50 mm and inside diameter d₁-30 mm. The solid steel core has diameter d₂-25 mm. The allowable shear stress of aluminum tube (1) is (rallow); = 100 MPa, and the allowable shear stress of steel core (2) is (Falkow)2= 135 MPa. Determine (a) the allowable torque T that can be applied to the composite shaft. (b) the corresponding torques produced in tube (1) and core (2). (c) the angle of twist produced by the allowable torque T. T di D₁ B Calculate the polar moment of inertia, J₁, of the aluminum tube. Answer: J₁ (106) mm.

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter1: Tension, Compression, And Shear
Section: Chapter Questions
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Part 1.
A composite assembly of length, L-375 mm, consisting of a steel (G-77 GPa) core (2) connected by rigid plates at the ends of an
aluminum [G-35 GPa) tube (1) is shown. The aluminum tube has outside diameter D₁ - 50 mm and inside diameter d₁-30 mm.
= 100 MPa, and the
The solid steel core has diameter d₂-25 mm. The allowable shear stress of aluminum tube (1) is (rallow)
allowable shear stress of steel core (2) is (Tallow)2= 135 MPa. Determine
(a) the allowable torque T that can be applied to the composite shaft.
(b) the corresponding torques produced in tube (1) and core (2).
(c) the angle of twist produced by the allowable torque T.
T
D₁
L
Calculate the polar moment of inertia, J₁, of the aluminum tube.
Answer: J₁
(106) mm².
Transcribed Image Text:Part 1. A composite assembly of length, L-375 mm, consisting of a steel (G-77 GPa) core (2) connected by rigid plates at the ends of an aluminum [G-35 GPa) tube (1) is shown. The aluminum tube has outside diameter D₁ - 50 mm and inside diameter d₁-30 mm. = 100 MPa, and the The solid steel core has diameter d₂-25 mm. The allowable shear stress of aluminum tube (1) is (rallow) allowable shear stress of steel core (2) is (Tallow)2= 135 MPa. Determine (a) the allowable torque T that can be applied to the composite shaft. (b) the corresponding torques produced in tube (1) and core (2). (c) the angle of twist produced by the allowable torque T. T D₁ L Calculate the polar moment of inertia, J₁, of the aluminum tube. Answer: J₁ (106) mm².
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