A confidence interval for a population mean has a length of 20 and a sample mean of 60. Obtain the confidence interval and determine the margin of error.
Q: Use the confidence interval to find the margin of error and the sample mean. (1.71, 1.99)
A: Solution: Given data: confidence Interval = (1.71, 1.99) To find: 1.Margin of error 2. Sample mean…
Q: Find the sample size needed if a 98% confidence interval has a 'margin of error' of 4% if .. a) You…
A: From the provided information, Margin of error (E) = 0.04 Confidence level = 98% The z value at 98%…
Q: Decreasing the sample size, while holding the confidence level the same, will do what to the length…
A: Introduction: Confidence interval is the interval estimate of the population parameter. It is the…
Q: Use the confidence interval to find the margin of error and the sample mean. (0.578,0.740)
A: Suppose the confidence interval is given as : (a,b) (x-MOE , x+MOE) = (0.578 , 0.740) Then to obtain…
Q: Use the given confidence interval to find the margin of error and the sample mean. (13.2,20.2) The…
A: Given: confidence interval = (13.2, 20.2)
Q: If X=127, σ=26, and n=38, construct a 95% confidence interval estimate of the population mean,…
A: The random variable X follows normal distribution. The sample mean is 127. The population standard…
Q: Use the given confidence interval to find the margin of error and the sample mean. (13.3,22.9)
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Q: An economist is interested in studying the incomes of consumers in a particular country. The…
A: It is given that the standard deviation is 1,000. Margin of error, E is 50. The confidence level is…
Q: Use the confidence interval to find the margin of error and the sample mean. (.228, 0.390)
A: We know that the Margin of error = (upper_limit - lower_imit )/2 and Sample mean = (upper limit +…
Q: The confidence interval for a population porportion is (0.34, 0.5). What the the sample proportion…
A: Given The confidence interval for a population proportion (0.34,0.5) estimate the sample…
Q: Given a sample size of 400 with a mean of 80 and the population standard deviation is found to be 35…
A: We have given that, Sample mean (x̄) = 80, population standard deviation (σ) = 35 and sample size…
Q: Increasing the sample size and decreasing the level of confidence are two ways of obtaining a…
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Q: A simple random sample of 800 elements generates a sample proportion .70. a. Provide a 90%…
A: It is given that sample size (n) is 800 and the sample proportion is 0.70.
Q: Construct a 95% confidence interval to estimate the population mean when x=133 and s = 35 for…
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Q: Use the given confidence interval to find the margin of error and the sample mean. (14.3,22.1) .....…
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Q: We weigh forty neonates and obtain a sample mean of 10 pounds with a standard deviation of 2 pounds.…
A: First, we find the critical value for 99% confidence interval.
Q: Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval…
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Q: Assuming that the population is normally distributed, construct a 90% confidence interval for the…
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Q: using the confidence interval method, to test that population mean equals 14, a researcher obtains…
A: Solution: State the hypotheses. Null hypothesis: H0: µ=14. That is, the population mean is equal to…
Q: Determine the margin of error for the confidence interval for the proportion: 0.557 < μ< 0.837 The…
A: It is given that the confidence interval for proportion is as follows: 0.557 < µ < 0.837.
Q: Assume that the population standard deviation is known and decide whether use of the z-interval…
A: The following assumptions are required for the large sample confidence interval about mean to be…
Q: Use the given confidence interval to find the population proportion margin of error. 0.54<p<0.68
A: Given: 0.54<p<0.68 To find: Margin of error
Q: 22. An investigator quantifies her uncertainty about the estimate of a population mean by reporting…
A: Confidence Interval:Confidence interval is the interval estimate of the population parameter. It is…
Q: Use the given confidence interval to find the margin of error and the sample mean. (6.23,10.55) The…
A: Solution: From the given information, the confidence interval is (6.23, 10.55).
Q: The 90% confidence interval for the population proportion p is (,) The 95% confidence interval for…
A: here n = 634 p^ = proportion of males gone to dentist pin past year = 390634 = 0.6151 z-critical for…
Q: Use the confidence interval to find the margin of error and the sample mean. (0.676,0.800)
A: The margin of error is the most common term which we use in a confidence interval. It is the degree…
Q: c. Find the confidence interval for the population mean with confidence level of 99%
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Q: For the confidence interval (24,44), the point estimate is and the margin of error is
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Q: You measure 25 textbooks' weights, and find they have a mean weight of 42 ounces. Assume the…
A: Given information: n=25x¯=42σ=5 Confidence level is 90% Significance level is 10%. From the z tale,…
Q: Use the given confidence interval to find the margin of error and the sample mean. (70.5,84.7)
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Q: Use the confidence interval to find the margin of error and the sample mean. (1.59,1.89)
A: Given data,Lower limit=1.59Upper limit=1.89Margin of error=?
Q: Use the given confidence interval to find the margin of error and the sample mean. (71.7, 87.3)
A:
Q: find the t/α2 value for a 95% confidence interval for the mean when the sample size is 10
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Q: Find a Confidence interval for the true Population Proportions if n = 30, x = 75, and the…
A: From the given information, X=75 and n=30.
Q: The width of a confidence interval for μ is not affected by A. The sample size. B. The confidence…
A: The formula of confidence interval for population is, CI=sample mean±ME=sample mean±critical…
Q: Use the confidence interval to find the margin of error and the sample mean. (.364,0.500)
A:
Q: Use the given confidence interval to find the margin of error and the sample mean. (13.0,20.4) The…
A: Plug in all the values in the formula, we get
Q: he standard deviation and the mean of 25 students scores are 10 and 38, respectively. Construct a…
A: Given that Sample size (n) = 25 Mean (x¯) = 38 Standard deviation (s) = 10 Confidence level (C) =…
Q: Use the confidence interval to find the margin of error and the sample mean. (0.456,0.620)
A: The confidence interval is given by (0.456, 0.620) Let M denote the sample mean, And E denote the…
Q: If the sample size is large, the confidence interval estimate for the difference between two…
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Q: ation, contruct a 90% confidence interval for the true
A: The value of z at a 90% confidence level is 1.645, which can be obtained by using the standard…
Q: The estimated prevalence is 25% and the desired confidence level is 95% with a margin of error of 4%…
A: The estimated prevalence =25% E= 4% CI =95% CI= 0.95 p= 0.25 E= 0.04
Q: Find the confidence level and α for an 80% confidence interval.
A: Given confidence level =80%
Q: If the sample size is large, the confidence interval estimate for the difference between two…
A: True
Q: Use the given confidence interval to find the margin of error and the sample mean. (14.2,24.0) The…
A: Given,confidence interval is (14.2 , 24.0)
Q: Assuming that the population is normally distributed, construct a 90% confidence interval for the…
A: Solution-: We find 90% confidence interval for the data 1,2,3,4,5,6,7,25 Also, we find confidence…
Q: Suppose you have a sample of size 100 with mean 5 and standard deviation 2. Construct a 95%…
A: Given: Sample size, n=100 Sample mean, X=5 Sample standard deviation, s=2 The degrees of freedom is…
Q: If X=80, σ=11,and n=62,construct a 95% confidence interval estimate of the population mean, μ.…
A: Given,sample size(n)=62sample mean(x¯)=80standard deviation(σ)=11α=1-0.95=0.05α2=0.025Z0.025=1.96…
Q: Use the given confidence interval to find the margin of error and the sample mean. (14.2,24.0) The…
A: Sample mean = (upper limit+lower limit)/2
A confidence interval for a population
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