A consumer has utility function u(T₁, 12) = (11 — C₁) (12 - 0₂) where c₁ and ₂ are positive constants. (a) Are this consumer's preferences monotone? Solution: No. Differentiating gives = 12 - C2, which is negative for 12 < €2. (b) Find this consumer's Hicksian demands and expenditure function if she must ch 1₁ ≥ 4₁ and 1₂ ≥ 0₂. Explain briefly how you would check that your solution is opti (you do not actually have to check it). Solution: The expenditure minimization problem is min p₁z₁+p2x2 st (₁-C₁) (12 - 0₂) ≥ u.

Microeconomic Theory
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ISBN:9781337517942
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Chapter4: Utility Maximization And Choice
Section: Chapter Questions
Problem 4.13P
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A consumer has utility function
u(x₁, x2) = (x₁ - C₁) (x₂ - 0₂)
where c₁ and ₂ are positive constants.
(a) Are this consumer's preferences monotone?
Solution: No. Differentiating gives = x2-02, which is negative for x2 < c₂.
(b) Find this consumer's Hicksian demands and expenditure function if she must choose
1₁ ≥ ₁ and 2₂ ≥ 02. Explain briefly how you would check that your solution is optimal
(you do not actually have to check it).
Solution: The expenditure minimization problem is
min p₁æ1+p2æ2 s.t (₁-₁)(x₂ - 0₂) ≥ u.
Since preferences are monotone for x₁ ≥ c₁ and x₂ ≥ c2, the constraint binds. The
first-order conditions are
and therefore
P1 = √(x₂ - 0₂)
and p2= (₁-C₁).
Dividing the two conditions gives
21 C1
P2
X2 C2 P1
Substituting back into the constraint gives
P2 (x₂-0₂)² = u
P1
h₂(p, u) = c₂ +
più
P2
Transcribed Image Text:A consumer has utility function u(x₁, x2) = (x₁ - C₁) (x₂ - 0₂) where c₁ and ₂ are positive constants. (a) Are this consumer's preferences monotone? Solution: No. Differentiating gives = x2-02, which is negative for x2 < c₂. (b) Find this consumer's Hicksian demands and expenditure function if she must choose 1₁ ≥ ₁ and 2₂ ≥ 02. Explain briefly how you would check that your solution is optimal (you do not actually have to check it). Solution: The expenditure minimization problem is min p₁æ1+p2æ2 s.t (₁-₁)(x₂ - 0₂) ≥ u. Since preferences are monotone for x₁ ≥ c₁ and x₂ ≥ c2, the constraint binds. The first-order conditions are and therefore P1 = √(x₂ - 0₂) and p2= (₁-C₁). Dividing the two conditions gives 21 C1 P2 X2 C2 P1 Substituting back into the constraint gives P2 (x₂-0₂)² = u P1 h₂(p, u) = c₂ + più P2
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