A coroner arrives at a murder scene at 11 p.m. She finds the temperature of the body to be 84.1°F. She waits one hour, takes the temperature again, and finds it to be 80.3°F. She notes that the room temperature is 67°F. Assuming that the temperature of the body was 98.6°F when the murder occured, when was the murder committed? The murder was commited at approximately approximately 8 p.m. (Do not round until the final answer. Then round to the nearest hour.)

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A: NOTE: Refresh your page if you can't see any equations. .  ambient temperature  initial temperature…

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A: The given equation is:sec2θ+25°=csc3θ+15°We need to solve the above equation.

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Q: Solve for t. (Enter your answers as a comma-separated list.)   700(1.09)t = 1,700

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A: We have to solve the equation.

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A: 1. At 8 PM Temperature = 28o C Per min drop = 2o C In 20 mins drop = 20*2 o C = 40o C  At 8.20 PM…

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Q: SC)=350 p.a for next years V(t)= 1- 0.01t PVo = 2 %3D

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