as shown in 30.8a, a given applied force of magnitude F results in a constant speed v and a power input P. Imagine that the force is increased so that the constant speed of the bar is doubled to 2υ. Under these conditions, what are the new force and the new power input? (a) 2F and 2P (b) 4F and 2P (c) 2F and 4P (d) 4F and 4P A counterclockwise current I isinduced in the loop. The magneticforce FR on the bar carrying thiscurrent opposes the motion.Figure 30.8 (a) A conductingbar sliding with a velocity v alongtwo conducting rails under theaction of an applied force FBecause of the current in the bar,there is a magnetic force F,onthe bar in the direction oppositeto the applied force. (b) Theequivalent circuit diagram for thesetup shown in (a).RF,appR|El = Blvappa

Name: as shown in 30.8a, a given applied force of magnitude F results in a c
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Description: as shown in 30.8a, a given applied force of magnitude F results in a constant speed v and a power input P. Imagine that the force is increased so that the constant speed of the bar is doubled to 2υ. Under these conditions, what are the new force and

Force in a uniform magnetic field is given as,

Answered: A counterclockwise current I is induced…

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter13: Electromagnetic Induction

Section: Chapter Questions

Problem 38P

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as shown in 30.8a, a given applied force of magnitude F results in a constant speed v and a power input P. Imagine that the force is increased so that the constant speed of the bar is doubled to 2υ. Under these conditions, what are the new force and the new power input? (a) 2F and 2P (b) 4F and 2P (c) 2F and 4P (d) 4F and 4P

A counterclockwise current I is
induced in the loop. The magnetic
force FR on the bar carrying this
current opposes the motion.
Figure 30.8 (a) A conducting
bar sliding with a velocity v along
two conducting rails under the
action of an applied force F
Because of the current in the bar,
there is a magnetic force F,on
the bar in the direction opposite
to the applied force. (b) The
equivalent circuit diagram for the
setup shown in (a).
R
F,
app
R
|El = Blv
app
a

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