A daily load curve which exhibited a 15-minute peak of 3000 kW is drawn to scale of 1 cm = 2 hours and 1 cm = 1000 kW. The total area under the load curve is measured by planimeter and is found to be 12 cm². Calculate the load factor based on 15-min. peak.

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter23: Resistive-inductive-capacitive Series Circuits
Section: Chapter Questions
Problem 7PP: Is the power factor in Question 6 a leading or lagging power factor? Explain your answer.
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A daily load curve which exhibited a 15-minute peak of 3000 kW is drawn to
scale of 1 cm = 2 hours and 1 cm = 1000 kW. The total area under the load curve is measured by
planimeter and is found to be 12 cm². Calculate the load factor based on 15-min. peak.
Transcribed Image Text:A daily load curve which exhibited a 15-minute peak of 3000 kW is drawn to scale of 1 cm = 2 hours and 1 cm = 1000 kW. The total area under the load curve is measured by planimeter and is found to be 12 cm². Calculate the load factor based on 15-min. peak.
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