A DC Optimal Power Flow problem is to be solved for a 3-bus network. The per-unit reactances of the lines interconnecting the buses are as follows: X12 = 0.1pu, X13 = 0.12 pu and X23 = 0.2 pu. There is a generator at each bus. The loads at buses 1, 2 and 3 are 150MW, 200mw, and 100MWrespectively. Bus 1 is taken as the reference bus, and SBase = 100 MVA. Which one of the below is a constraint of the DCOPF problem? Select one: O a. None of these O b.-500 0₂-1000 03 = P3-110 O c. 1500 0₂-500 03 = P₂-220 O d. 1500 8₂-500 03 = P2 - 200 O e. -500 0₂-1000 03 = P3 - 150 O f.-1500 8₁-1000 03= P₁ - 150

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter7: Symmetrical Faults
Section: Chapter Questions
Problem 7.30P
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A DC Optimal Power Flow problem is to be solved for a 3-bus network. The per-unit reactances of the lines interconnecting the buses are
as follows:
X12 = 0.1pu, X13 = 0.12 pu and X23 = 0.2 pu.
There is a generator at each bus. The loads at buses 1, 2 and 3 are 150MW, 200mw, and 100MWrespectively. Bus 1 is taken as the
reference bus, and SBase = 100 MVA. Which one of the below is a constraint of the DCOPF problem?
Select one:
O a. None of these
O b. -500 0₂-1000 03 = P3 - 110
O c. 1500 0₂-500 03 = P₂ - 220
O d.
1500 0₂-500 03 = P₂ - 200
O e. -500 0₂-1000 03 = P3 - 150
O f. -1500 8₁-1000 03 = P₁ - 150
Transcribed Image Text:A DC Optimal Power Flow problem is to be solved for a 3-bus network. The per-unit reactances of the lines interconnecting the buses are as follows: X12 = 0.1pu, X13 = 0.12 pu and X23 = 0.2 pu. There is a generator at each bus. The loads at buses 1, 2 and 3 are 150MW, 200mw, and 100MWrespectively. Bus 1 is taken as the reference bus, and SBase = 100 MVA. Which one of the below is a constraint of the DCOPF problem? Select one: O a. None of these O b. -500 0₂-1000 03 = P3 - 110 O c. 1500 0₂-500 03 = P₂ - 220 O d. 1500 0₂-500 03 = P₂ - 200 O e. -500 0₂-1000 03 = P3 - 150 O f. -1500 8₁-1000 03 = P₁ - 150
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