A dead battery is charged by connecting it to the hive tery of another car with jumper cables (Fig. P28.24). Dete mine the current in the starter and in the dead battery 0.01 Q 1.00 N 0.06 N Starter 10 V -T 12 V -T Live battery Dead battery

A dead battery is charged by connecting it to the hive tery of another car with jumper cables (Fig. P28.24). Dete mine the current in the starter and in the dead battery 0.01 Q 1.00 N 0.06 N Starter 10 V -T 12 V -T Live battery Dead battery

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter28: Direct-current Circuits

Section: Chapter Questions

Problem 28.63AP: The- pair of capacitors in Figure P28.63 are fully charged by a 12.0-V battery. The battery is...

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Considering the same circuit, only with the switch thrown from b to a at time t = 0 after having been in position b for a long time. DATA: Vb = 12 V, C = 10 µF, R = 20 Ω.a.) What is the curnent through the resistor just BEFORE the switch is thrown?b.) What is the current through the resistor just AFTER the switch is thrown?c.) What is the charge across the capacitor just BEFORE the switch is thrown?d.) What is the charge on the capacitor just AFTER the switch is thrown?e.) What is the charge on the capacitor at at time t = 0.3 msec after the switch is thrown?
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You connect a battery, resistor, and capacitor as in Fig. 26.20a, where E = 36.0 V, C = 5.00 mF, and R = 120 Ω. The switch S is closed at t = 0. (a) When the voltage across the capacitor is 8.00 V, what is the magnitude of the current in the circuit? (b) At what time t after the switch is closed is the voltage acrossthe capacitor 8.00 V? (c) When the voltage across the capacitor is 8.00 V, at what rate is energy being stored in the capacitor?
A 170-kV power transmission line carrying 500 A is hung from grounded metal towers by ceramic insulators, each having a 1.05 109 Ω resistance. (a) What is the resistance to ground of 60 of these insulators? (Assume the insulators are connected in parallel.) (b) Calculate the power dissipated by 60 of them.(c) What fraction of the power carried by the line is this?
Switch S shown in Figure P28.71 has been closed for a long lime, and the electric circuit carries a constant current. Take C1 = 3.00 μF, C2 = 6.00 μF, R1 = 4.00 kΩ, and R2 , = 7.00 kΩ. The power delivered to R2 , is 2.40 W. (a) Find the charge on C1 . (b) Now the switch is opened. After many milliseconds, by how much has the charge on C2 changed?
A particle accelerator produces a beam with a radius of 1.25 mm with a current of 2.00 mA. Each proton has a kinetic energy of 10.00 MeV. (a) What is the velocity of the protons? (b) What is the number (n) of protons per unit volume? (b) How many electrons pass a cross sectional area each second?
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In the circuit of Figure P27.25, the switch S has been open for a long time. It is then suddenly closed. Take = 10.0 V, R1 = 50.0 k, R2 = 100 k, and C = 10.0 F. Determine the time constant (a) before the switch is closed and (b) after the switch is closed. (c) Let the switch be closed at t = 0. Determine the current in the switch as a function of time. Figure P27.25 Problems 25 and 26.
Figure P18.37 shows a simplified model of a cardiac defibrillator, a device used to patients in ventricular fibrillation. When the switch S is toggled to the left, the capacitor C charges through the resistor R .When the switch is toggled to the right, the capacitor discharges current through the patients torso, modeled as the resistor Rtorso, allowing the hearts normal rhythm to be reestablished. (a) If the capacitor is initially uncharged with C = 8.00 F and = 1250 V, find the value of R required to charge the capacitor to a voltage of 775 V in 1.50 s. (b) If the capacitor is then discharged across the patients torso with, Rtorso = 1250 , calculate the voltage across the capacitor after 5.00 ms. Figure P18.37
Figure P18.37 shows a simplified model of a cardiac defibrillator, a device used to patients in ventricular fibrillation. When the switch S is toggled to the left, the capacitor C charges through the resistor R .When the switch is toggled to the right, the capacitor discharges current through the patients torso, modeled as the resistor Rtorso, allowing the hearts normal rhythm to be reestablished. (a) If the capacitor is initially uncharged with C = 8.00 F and = 1250 V, find the value of R required to charge the capacitor to a voltage of 775 V in 1.50 s. (b) If the capacitor is then discharged across the patients torso with, Rtorso = 1250 , calculate the voltage across the capacitor after 5.00 ms. Figure P18.37