Question
Asked Dec 19, 2019
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A dead battery is charged by connecting it to the live battery
of another car with jumper cables (Fig. P18.28). Determine
the current in (a) the starter and in (b) the dead battery.

1.0 2
0.010 2
0.060 N
-Starter
10. V
12 V
Dead
Live
battery
battery
Ignition
switch
Figure P18.28
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1.0 2 0.010 2 0.060 N -Starter 10. V 12 V Dead Live battery battery Ignition switch Figure P18.28

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Expert Answer

Step 1
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A B 0.010 0 1.0 N 0.060 2 -Starter 10. V 12 V Live battery Dead battery D Ignition switch

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Step 2
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(a) Applying the Kirchoff's voltage law in the loop ACDFA: 12–1, (0.010)– 1, (0.060) = 0 0.011, + 0.061, =12 (i) .. Applying the Kirchoff's voltage law in the loop BCDEB: 10+1, (1.0) – I, (0.060)=0 I, -0.061, = -10 .(i) I,= 0.061,-10 .......

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Step 3
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From Kirchoff s current law: I = I, + I; Plugging in the value of Ii in equation (i) 0.01(I, + I; )+0.061, = 12 0.011, +0.071, = 12 Plugging in the value of I, from (iii): 0.01( 0.061; -10)+ 0.071, = 12 0.00061; – 0.1+0.071, = 12 0.0706I; = 12.1 I; = 171.388 A

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