A dentist uses a curved mirror to view teeth on the upper side ofthe mouth. Suppose she wants an upright image with amagnification of 2.20 when the mirror is 1.10 cm from a tooth.(Treat this problem as though the object and image lie along astraight line.)For related problem-solving tips and strategies, you may want toview a Video Tutor Solution ofGraphical construction of an image from a mirror.What kind of mirror is needed? Use a ray diagram to decide, without performing any calculations.concaveconvexSubmitPrevious AnswersCorrect111Set Up: +/=/ and m =SSolve: s'Part B=sfs-fand m = -|f|= -f so m = +·Y17 ΑΣΦf, R=2.42,4.84=-.m = +2.20 and s = 1.10cm. An upright image must be virtual.For a concave mirror, m can be larger than 1.00. For a convex mirror,s-f|f|s+|f|and m is always less than 1.00. The mirror must be concave (f> 0).What must be the focal length and radius of curvature of this mirror?Enter your answer in centimeters separated by a comma.Submit Previous Answers Request AnswerX Incorrect; Try Again; 4 attempts remaining?cm

B) Write the expression for the magnification and substitute the corresponidng values to calculate…

A dentist uses a curved mirror to view teeth on the upper side of the mouth. Suppose she wants an upright image with a magnification of 2.20 when the mirror is 1.10 cm from a tooth. (Treat this problem as though the object and image lie along a straight line.) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Graphical construction of an image from a mirror. What kind of mirror is needed? Use a ray diagram to decide, without performing any calculations. concave O convex Submit Previous Answers ✓ Correct y Set Up: += ₁ and m = == .m +2.20 and s= 1.10cm. An upright image must be virtual. y Solve: s' = Part B 음 and m- |f|= -f so m = + 허 . For a concave mirror, can be larger than 1.00. For a convex mirror, Ifl s+|f and m is always less than 1.00. The mirror must be concave (f > 0). What must be the focal length and radius of curvature of this mirror? Enter your answer in centimeters separated by a comma. 17| ΑΣΦ f. R= 2.42,4.84 Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining ? cm

A dentist uses a curved mirror to view teeth on the upper side of the mouth. Suppose she wants an upright image with a magnification of 2.20 when the mirror is 1.10 cm from a tooth. (Treat this problem as though the object and image lie along a straight line.) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Graphical construction of an image from a mirror. What kind of mirror is needed? Use a ray diagram to decide, without performing any calculations. concave O convex Submit Previous Answers ✓ Correct y Set Up: += ₁ and m = == .m +2.20 and s= 1.10cm. An upright image must be virtual. y Solve: s' = Part B 음 and m- |f|= -f so m = + 허 . For a concave mirror, can be larger than 1.00. For a convex mirror, Ifl s+|f and m is always less than 1.00. The mirror must be concave (f > 0). What must be the focal length and radius of curvature of this mirror? Enter your answer in centimeters separated by a comma. 17| ΑΣΦ f. R= 2.42,4.84 Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining ? cm

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter26: Image Formation By Mirrors And Lenses

Section: Chapter Questions

Problem 1OQ

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Similar questions

Suppose a man stands in front of a mirror as shown in Figure 25.50. His eyes are 1.65 m above the floor, and the top of his head is 0.13 m higher. Find the height above the floor of the top and bottom of the smallest mirror in which he can see both the top of his head and his feet. How is this distance related to the man’s height? Figure 25.50 A full-length mirror is one in which you can see all of yourself. It need not be as big as you, and its size is independent of your distance from it.
Use the law of reflection to prove that the focal length of a mirror is half its radius of curvature. That is, prove that f = R/2. Note this is true for a spherical mirror only if its diameter is small compared with its radius of curvature.
The disk of the Sun subtends an angle of 0.533 at the Earth. What are (a) the position and (b) the diameter of the solar image formed by a concave spherical mirror with a radius of curvature of magnitude 3.00 m?
Show that the magnification of a thin lens is given by M = di/do (Eq. 38.6). Hint: Follow the derivation of the lens makers equation (page 1233) and start with a thick lens.
A converging lens has a focal length of 10.0 cm. Locate the object if a real image is located at a distance from the lens of (a) 20.0 cm and (b) 50.0 cm. What If? Redo the calculations if the images are virtual and located at a distance from the lens of (c) 20.0 cm and (d) 50.0 cm.
A 1.80-m-tall person stands 9.00 m in front of a large, concave spherical mirror having a radius of curvature of 3.00 m. Determine (a) the mirrors focal length, (b) the image distance, and (c) the magnification. (d) Is the image real or virtual? (e) Is the image upright or inverted?
(a) A concave spherical mirror forms ail inverted image different in size from the object by a factor a 1. I'he distance between object and image is d. Find the local length of the mirror, (b) What If? Suppose the mirror is convex, an upright image is formed, and a 1. Determine the focal length of the minor.
A leaf of length h is positioned 71.0 cm in front of a converging lens with a focal length of 39.0 cm. An observer views the image of the leaf from a position 1.26 in behind the lens, as shown in Figure P25.25. (a) What is the magnitude of the lateral magnification (the ratio of the image size to the object size) produced by the lens? (b) What angular magnification is achieved by viewing the image of the leaf rather than viewing the loaf directly? Figure P25.25
Two converging lenses having focal length of f1 = 10.0 cm and f2 = 20.0 cm are placed d = 50.0 cm apart, as shown in Figure P23.44. The final image is to be located between the lenses, at the position x = 31.0 cm indicated. (a) How far to the left of the first lens should the object be positioned? (b) What is the overall magnification of the system? (c) Is the final image uptight or inserted? Figure P23.44
A lamp of height S cm is placed 40 cm in front of a converging lens of focal length 20 cm. There is a plane mirror 15 cm behind the lens. Where would you find the image when you look in the mirror?
What is the focal length of a makeup mirror that produces a magnification of 1.50 when a person’s face is 12.0 cm away? Explicitly show how you follow the steps in the Problem-Solving Strategy: Spherical Mirrors.
For a normal, relaxed eye, a magnifying glass produces an angular magnification of 4.0. What is the largest magnification possible with this magnifying glass?