A dielectric slab of Teflon ( K=2.1 ) is inserted between the plates of a parallel-plate capacitor with a plate separation 0.03 cm and plate area 2.3 cm? .What is the new capacitance? O A) 6.8 pF O B) 142 nF O 9 1.42 uF O D) 14.2 pF O E) 1.42 nF

A dielectric slab of Teflon ( K=2.1 ) is inserted between the plates of a parallel-plate capacitor with a plate separation 0.03 cm and plate area 2.3 cm? .What is the new capacitance? O A) 6.8 pF O B) 142 nF O 9 1.42 uF O D) 14.2 pF O E) 1.42 nF

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter20: Electric Potential And Capacitance

Section: Chapter Questions

Problem 17OQ: An electronics technician wishes to construct a parallel plate capacitor using rutile ( = 100) as...

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Question

A dielectric slab of Teflon (
K=2.1
) is inserted between the plates of a parallel-plate capacitor with a plate separation 0.03 cm and plate area
9-
2.3 cm?
.What is the new capacitance?
O A) 6.8 pF
O B) 142 nF
O 9 1.42 µF
O D) 14.2 pF
O E) 1.42 nF

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