A different way to produce ethanol (C2H60, M.M. = 46.08 g/mol) is through fermentation of sugar (C6H1206, M.M. = 180.18 g/mol) Balance the following chemical equation: + C6H12O6(aq) → : C2H6O(aq) + CO2(g) Using your balanced chemical equation from the previous question, determine what mass of C6H1206 (in grams) is needed to make 10.0 g of ethanol. Make sure to report your answer to the correct number of significant figures and with the correct units. Answer: Using your answer from the previous question, determine the percent yield of the reaction if you actually produce 7.50 g of ethanol. Make sure to report your answer to the correct number of significant figures and with the correct units. Answer:

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Chapter3: Calculations With Chemical Formulas And Equaitons
Section: Chapter Questions
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A different way to produce ethanol (C2H60, M.M. = 46.08 g/mol) is through fermentation of sugar (C6H1206, M.M. = 180.18 g/mol)
Balance the following chemical equation:
+ C6H12O6(aq) →
: C2H6O(aq) +
CO2(g)
Using your balanced chemical equation from the previous question, determine what mass of C6H1206 (in grams) is needed to make 10.0 g of ethanol.
Make sure to report your answer to the correct number of significant figures and with the correct units.
Answer:
Using your answer from the previous question, determine the percent yield of the reaction if you actually produce 7.50 g of ethanol. Make sure to
report your answer to the correct number of significant figures and with the correct units.
Answer:
Transcribed Image Text:A different way to produce ethanol (C2H60, M.M. = 46.08 g/mol) is through fermentation of sugar (C6H1206, M.M. = 180.18 g/mol) Balance the following chemical equation: + C6H12O6(aq) → : C2H6O(aq) + CO2(g) Using your balanced chemical equation from the previous question, determine what mass of C6H1206 (in grams) is needed to make 10.0 g of ethanol. Make sure to report your answer to the correct number of significant figures and with the correct units. Answer: Using your answer from the previous question, determine the percent yield of the reaction if you actually produce 7.50 g of ethanol. Make sure to report your answer to the correct number of significant figures and with the correct units. Answer:
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