   Chapter 3, Problem 133E

Chapter
Section
Textbook Problem

Bornite (Cu3FeS3) is a copper ore used in the production of copper. When heated, the following reaction occurs: 2 Cu 3 FeS 3 ( s )   +  7O 2 ( g ) → 6 Cu ( s )   +   2 FeO ( s )   +   6 SO 2 If 2.50 metric tons of bornite is reacted with excess O2 and the process has an 86.3% yield of copper, what mass of copper is produced?

Interpretation Introduction

Interpretation: The reaction depicting the production of copper by heating bornite (Cu3FeS3) is given. The mass of copper produced is to be calculated.

Concept introduction: The mass of a substance can be obtained by using the number of moles of the substance present and its molar mass. The formula used to calculate the mass of a given substance is,

Massofthesubstance=(Numberofmoles)×(Molarmassofthesubstance)

To determine: The mass of copper produced in the given chemical process.

Explanation

Given

The balanced chemical equation is,

2Cu3FeS3(s)+7O2(g)6Cu(s)+2FeO(s)+6SO2(g)

The given mass of Cu3FeS3 is 2.50metrictons(2.50×106g) .

The given yield of copper is 86.3% .

The molar mass of Cu3FeS3 =3Cu+Fe+3S=((3×63.55)+56+(3×32))g/mol=342.65g/mol

Formula

The number of moles of a substance is calculated by the formula,

Numberofmoles=GivenmassofthesubstanceMolarmassofthesubstance

Substitute the value of the given mass and the molar mass of Cu3FeS3 in the above expression.

NumberofmolesofCu3FeS3=2.50×106g342.65g/mol=7.29×103mol

According to the stated reaction,

2mol of Cu3FeS3 produce 6mol of Cu .

1mol of Cu3FeS3 produces Cu =(62)mol

7

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts 