A dog running in an open field has components of velocity vỵ = 2.6m/s and v, = -1.8m/s at t = 10.0s. For the time interval from tį = 10.0s at t, = 20.0s, the average acceleration of the dog has magnitude 0.45m/s' and direction 31.0° measure from the +x-axis toward the +y-axis. At t = 20.0s, a. What are the x- and y- components of the dog's velocity? b. What are the magnitude and direction of the dog's velocity?

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter3: Motion In Two Dimensions
Section: Chapter Questions
Problem 2P: A hiker walks 2.00 km north and then 3.00 km east, all in 2.50 hours. Calculate the magnitude and...
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Y A dog running in an open field has components of velocity vx = 2.6m/s and v, = -1.8m/s at
t = 10.0s. For the time interval from t = 10.0s at t, = 20.0s, the average acceleration of the dog
has magnitude 0.45m/s and direction 31.0° measure from the +x-axis toward the +y-axis. At
t = 20.0s,
What are the x- and y- components of the dog's velocity?
b. What are the magnitude and direction of the dog's velocity?
Transcribed Image Text:Y A dog running in an open field has components of velocity vx = 2.6m/s and v, = -1.8m/s at t = 10.0s. For the time interval from t = 10.0s at t, = 20.0s, the average acceleration of the dog has magnitude 0.45m/s and direction 31.0° measure from the +x-axis toward the +y-axis. At t = 20.0s, What are the x- and y- components of the dog's velocity? b. What are the magnitude and direction of the dog's velocity?
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