A field investigation of the thermal environment has been conducted for a room with an external wall facing east. The wall are made of 150 mm brick (k = 0.9 W/m°C) and 15 mm of plaster (k= 0.3 W/m°C) on both sides. The results are as shown in Figure Q1(a) and Figure Q1(b), representing the temporal wall surface temperature and indoor air temperature respectively. (i)Based on the graph in Figure Q1(a), analyze the value of the conductive heat flow (Q) for the wall at 11:00 a.m. and 15:00 p.m. and discuss ONE (1) potential cause of the difference. Given the value of external and internal surface resistance are 0.06 m2°C/W and 0.12 m2°C/W, respectively. Meanwhile, the area of the wall is 12m2 . (ii) Based on your reason in Q1(i), propose TWO (2) practicable strategies that can reduce the external wall surface temperature during that time. (iii) As shown in Figure Q1(b), the indoor air temperature of the room reached its peak (maximum temperature) at about 1.5 hours later than that of outdoor air temperature. Explain ONE (1) reason for this delayed effect

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Q1 A field investigation of the thermal environment has been conducted for a room with

an external wall facing east. The wall are made of 150 mm brick (k = 0.9 W/m°C) and

15 mm of plaster (k= 0.3 W/m°C) on both sides. The results are as shown in Figure

Q1(a) and Figure Q1(b), representing the temporal wall surface temperature and

indoor air temperature respectively.

(i)Based on the graph in Figure Q1(a), analyze the value of the conductive heat

flow (Q) for the wall at 11:00 a.m. and 15:00 p.m. and discuss ONE (1)

potential cause of the difference. Given the value of external and internal

surface resistance are 0.06 m2°C/W and 0.12 m2°C/W, respectively.

Meanwhile, the area of the wall is 12m2 .

(ii) Based on your reason in Q1(i), propose TWO (2) practicable strategies that

can reduce the external wall surface temperature during that time.

(iii) As shown in Figure Q1(b), the indoor air temperature of the room reached its

peak (maximum temperature) at about 1.5 hours later than that of outdoor air

temperature. Explain ONE (1) reason for this delayed effect.

(iv) As shown in Figure Q1(b), the indoor air temperatures were higher than

outdoor from 20:00 p.m. Explain ONE (1) possible reason for this event.

(v) Suggest ONE (1) strategy to reduce the indoor air temperature at night.

External wall
surface
Internal wall
surface
Time
FIGURE Q1(a)
Surface temperature (°C)
00:8
8:30
00:6
9:30
10:00
10:30
11:00
11:30
12:00
12:30
13:00
13:30
14:00
14:30
15:00
15:30
16:00
16:30
17:00
Transcribed Image Text:External wall surface Internal wall surface Time FIGURE Q1(a) Surface temperature (°C) 00:8 8:30 00:6 9:30 10:00 10:30 11:00 11:30 12:00 12:30 13:00 13:30 14:00 14:30 15:00 15:30 16:00 16:30 17:00
Outdoor
Indoor
Time
FIGURE Q1(b)
Air temperature (°C)
00:8
8:30
00:6
9:30
10:00
10:30
11:00
11:30
00:
12:30
13:00
13:30 -
14:00
14:30
15:00
15:30
16:00-
16:30
17:00
17:30
18:00
18:30 -
19:00 -
19:30
00:07
20:30
21:00
21:30
22:00
22:30
23:00-
23:30
0:00
Transcribed Image Text:Outdoor Indoor Time FIGURE Q1(b) Air temperature (°C) 00:8 8:30 00:6 9:30 10:00 10:30 11:00 11:30 00: 12:30 13:00 13:30 - 14:00 14:30 15:00 15:30 16:00- 16:30 17:00 17:30 18:00 18:30 - 19:00 - 19:30 00:07 20:30 21:00 21:30 22:00 22:30 23:00- 23:30 0:00
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