A fire walker runs across a bed of hot coals without sustaining burns. In this problem, you may assume the body temperature of a human is a constant 37.0°C. (a) Calculate the heat heat, in joules, transferred by conduction into the sole of one foot of a firewalker, given that the bottom of the foot is a 2.9-mm-thick callus, with a conductivity at the lowest end of the range for wood and with a density of 295 kg/m3. The area of contact is 23 cm2, the temperature of the coals is 700°C, and the time in contact is 1.05 s. The firewalker’s body temperature is 37°C.  (b) What temperature increase, in degrees Celsius, is produced in the 23 cm3 of tissue affected? The specific heat of human tissue is typically 3500 J/(kg⋅°C).

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ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
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Chapter14: Heat And Heat Transfer Methods
Section: Chapter Questions
Problem 6PE: A 0.250kg block at a pure material is heated from 20.0C to 65.0C by the addition of 4.35 kJ of...
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A fire walker runs across a bed of hot coals without sustaining burns. In this problem, you may assume the body temperature of a human is a constant 37.0°C.

(a) Calculate the heat heat, in joules, transferred by conduction into the sole of one foot of a firewalker, given that the bottom of the foot is a 2.9-mm-thick callus, with a conductivity at the lowest end of the range for wood and with a density of 295 kg/m3. The area of contact is 23 cm2, the temperature of the coals is 700°C, and the time in contact is 1.05 s. The firewalker’s body temperature is 37°C. 

(b) What temperature increase, in degrees Celsius, is produced in the 23 cm3 of tissue affected? The specific heat of human tissue is typically 3500 J/(kg⋅°C). 

Thermal conductivity k
(J/s•m•°C)
Substance
Glass wool
0.042
Wool
0.04
0.84
Glass
Human body
0.2
0.84
Ceramic
Wood
0.08-0.16
Air
0.023
Fatty tissue
Styrofoam
0.2
0.010
Transcribed Image Text:Thermal conductivity k (J/s•m•°C) Substance Glass wool 0.042 Wool 0.04 0.84 Glass Human body 0.2 0.84 Ceramic Wood 0.08-0.16 Air 0.023 Fatty tissue Styrofoam 0.2 0.010
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